想把摄像头采集的数据放到QT上面显示!摄像头可以显示,但是总会出现这个错误,网上说要增加Qwidget的属性,但是不知道怎么加!!代码如下,希望大神指教一下
#include <QtGui>
#include "processImage.h"
#include "videodevice.h"
extern "C"
{
#include <stdio.h>
#include <stdlib.h>
}
ProcessImage::ProcessImage(QWidget *parent):QWidget(parent)
{
//this->setAttribute(Qt::WA_PaintOutsidePaintEvent);
pp = (unsigned char *)malloc(320 * 240/*QWidget::width()*QWidget::height()*/* 3 * sizeof(char));
painter = new QPainter(this);
frame = new QImage(pp,320,240,QImage::Format_RGB888);
//frame = new QPixmap(640,240);
label = new QLabel();
vd = new VideoDevice(tr("/dev/video0"));
connect(vd, SIGNAL(display_error(QString)), this,SLOT(display_error(QString)));
rs = vd->open_device();
if(-1==rs)
{
QMessageBox::warning(this,tr("error"),tr("open /dev/dsp error"),QMessageBox::Yes);
vd->close_device();
}
rs = vd->init_device();
if(-1==rs)
{
QMessageBox::warning(this,tr("error"),tr("init failed"),QMessageBox::Yes);
vd->close_device();
}
rs = vd->start_capturing();
if(-1==rs)
{
QMessageBox::warning(this,tr("error"),tr("start capture failed"),QMessageBox::Yes);
vd->close_device();
}
if(-1==rs)
{
QMessageBox::warning(this,tr("error"),tr("get frame failed"),QMessageBox::Yes);
vd->stop_capturing();
}
timer = new QTimer(this);
connect(timer,SIGNAL(timeout()),this,SLOT(update()));
timer->start(30);
QHBoxLayout *hLayout = new QHBoxLayout();
hLayout->addWidget(label);
setLayout(hLayout);
setWindowTitle(tr("Capture"));
}
ProcessImage::~ProcessImage()
{
rs = vd->stop_capturing();
rs = vd->uninit_device();
rs = vd->close_device();
}
void ProcessImage::paintEvent(QPaintEvent *)
{
rs = vd->get_frame((void **)&p,&len);
convert_yuv_to_rgb_buffer(p,pp,320,240/*QWidget::width(),QWidget::height()*/);
frame->loadFromData((uchar *)p,/*len*/320 * 240 * 3 * sizeof(char));
// painter->begin(this);
// painter->drawImage(0,0,*frame);
// painter->end();