问题描述
如果用户键入的不是1-5，我希望该程序可以打印出一个答案，说“对不起，我无法识别该输入”。
import time
rating=input()
if rating == '1':
time.sleep(.5)
print('Well, you mustve just had a bad day.')
if rating =='2':
time.sleep(.5)
print('Second to last means I wasnt even the best at losing...')
if rating =='3':
time.sleep(.5)
print('Atleast thats almost passing.')
if rating =='4':
time.sleep(.5)
print('Im offended.')
if rating =='5':
time.sleep(.5)
print('Well yeah, obviously.')
1楼
使用if ， elif以及else ，如果输入的内容不是1，2，3，4，5，则代码中的else将打印您要显示的消息。
下面的代码也将由于elif阻止检查所有其他数字。
在您的代码中，您正在检查5 if语句中的所有数字。
import time
rating=input()
if rating == '1':
time.sleep(.5)
print('Well, you mustve just had a bad day.')
elif rating =='2':
time.sleep(.5)
print('Second to last means I wasnt even the best at losing...')
elif rating =='3':
time.sleep(.5)
print('Atleast thats almost passing.')
elif rating =='4':
time.sleep(.5)
print('Im offended.')
elif rating =='5':
time.sleep(.5)
print('Well yeah, obviously.')
else:
print ('Sorry I dont recognize that input')
再次询问用户，直到输入正确的号码为止 （根据下面的评论）
while rating:
if rating == '1':
time.sleep(.5)
print('Well, you mustve just had a bad day.')
break
elif rating =='2':
time.sleep(.5)
print('Second to last means I wasnt even the best at losing...')
break
elif rating =='3':
time.sleep(.5)
print('Atleast thats almost passing.')
break
elif rating =='4':
time.sleep(.5)
print('Im offended.')
break
elif rating =='5':
time.sleep(.5)
print('Well yeah, obviously.')
break
else:
print ('Sorry I dont recognize that input. Enter the rating again.')
rating=input()
continue
输出（第二种情况）
6
Sorry I dont recognize that input. Enter the rating again.
6
Sorry I dont recognize that input. Enter the rating again.
5
Well yeah, obviously.