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+不支持的操作数类型:'RegexURLPattern'和'str'

热度:51   发布时间:2023-06-13 14:01:40.0

嗨,我无法解决此问题,

我遵循了教程。

我不记得了,但是我想我读过某个地方,如果您使用功能视图,则必须导入某些内容,但不确定此处是否是这种情况,或者这是否成立。

这是我的帐户应用程序中urls.py的代码

from django.conf.urls import patterns, url
from accounts import views

urlpatterns = patterns(
   url(r'^register$', 'accounts.views.register', name='register'),
   url(r'^login$', 'accounts.views.login', name='login'),
   url(r'^logout$', 'accounts.views.logout', name='logout'),

在主要的urls.py中

from django.conf.urls import patterns, include, url
from django.contrib import admin

urlpatterns = ['',
    url(r'^accounts/', include('accounts.urls', namespace='accounts')),
    url(r'^admin/', include(admin.site.urls)),
  ]

下面是错误消息和回溯

Environment:
Django Version: 1.8.5
Python Version: 3.4.0

Request Method: GET
Request URL: http://127.0.0.1:8777/

Django Version: 1.8.5
Python Version: 3.4.0


Request Method: GET
Request URL:    http://127.0.0.1:8777/
Django Version: 1.8.5
Exception Type: TypeError
Exception Value:    
unsupported operand type(s) for +: 'RegexURLPattern' and 'str'
Exception Location: /home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/core/urlresolvers.py in add_prefix, line 223
Python Executable:  /home/kevin/djangoP/envRU/bin/python
Python Version: 3.4.0


Traceback:

    File "/home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/core/handlers/base.py" in get_response
      119.                 resolver_match = resolver.resolve(request.path_info)

    File "/home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/core/urlresolvers.py" in resolve
      365.             for pattern in self.url_patterns:


    File "/home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/core/urlresolvers.py" in url_patterns
      401.         patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)

    File "/home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/core/urlresolvers.py" in urlconf_module
      395.             self._urlconf_module = import_module(self.urlconf_name)

    File "/home/kevin/djangoP/envRU/lib/python3.4/importlib/__init__.py" in import_module
      109.     return _bootstrap._gcd_import(name[level:], package, level)

    File "/home/kevin/djangoP/ru/rulinked/rulinked/urls.py" in <module>
      20.     url(r'^accounts/', include('accounts.urls', namespace='accounts')),


    File "/home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/conf/urls/__init__.py" in include
      33.         urlconf_module = import_module(urlconf_module)


    File "/home/kevin/djangoP/envRU/lib/python3.4/importlib/__init__.py" in import_module
      109.     return _bootstrap._gcd_import(name[level:], package, level)


    File "/home/kevin/djangoP/ru/rulinked/accounts/urls.py" in <module>
      7.     url(r'^logout$', 'accounts.views.logout', name='logout'),

    File "/home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/conf/urls/__init__.py" in patterns
      61.             t.add_prefix(prefix)

    File "/home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/core/urlresolvers.py" in add_prefix
      223.         self._callback_str = prefix + '.' + self._callback_str

    Exception Type: TypeError at /
    Exception Value: unsupported operand type(s) for +: 'RegexURLPattern' and 'str'

如果您读了那么远,那么谢谢,我知道很多,但我真的迷失了方向,不知道还能从哪里获得帮助。

您会混淆两种可用的语法。

patterns()函数将前缀作为第一个参数,它是一个(可能为空)字符串,并返回一个列表,其中将前缀添加到每个模式中。 其他参数是url()实例。 普通列表应仅包含url()实例,并且不能添加公共前缀。

patterns()已被弃用,因此最好在任何地方使用一个列表:

account / urls.py

urlpatterns = [
   url(r'^register$', 'accounts.views.register', name='register'),
   url(r'^login$', 'accounts.views.login', name='login'),
   url(r'^logout$', 'accounts.views.logout', name='logout'),
]

urls.py

urlpatterns = [
    url(r'^accounts/', include('accounts.urls', namespace='accounts')),
    url(r'^admin/', include(admin.site.urls)),
]

至于导入视图:如果传递函数本身,则需要导入它们。 如果不先导入,则该功能不可用,并导致NameError 现在,您传递的是导入路径,而不是函数,因此您不必导入任何内容。 这也已弃用(用于视图,而不用于其他URL配置),因此为了与将来的Django版本兼容,您可以将其更改为:

from django.conf.urls import url
from accounts import views

urlpatterns = [
   url(r'^register$', views.register, name='register'),
   url(r'^login$', views.login, name='login'),
   url(r'^logout$', views.logout, name='logout'),
]

请注意, url()的第二个参数不再是字符串,而是导入的views模块中的view函数本身。

将您的应用urls.py修改为:

from django.conf.urls import patterns, url
from accounts import views

urlpatterns = patterns('', // add the empty string here
   url(r'^register$', 'accounts.views.register', name='register'),
   url(r'^login$', 'accounts.views.login', name='login'),
   url(r'^logout$', 'accounts.views.logout', name='logout'),
)

另外,从您的主要urls.py中删除空字符串:

from django.conf.urls import patterns, include, url
from django.contrib import admin

urlpatterns = [
    url(r'^accounts/', include('accounts.urls', namespace='accounts')),
    url(r'^admin/', include(admin.site.urls)),
  ]

因为我不认为使用方括号版本时需要它。