php通过表单提交参数查询解决方案 _PHP

php通过表单提交参数查询
如题想做个简单的查询系统：
现在搞了个没有表单的，代码如下：

PHP code

<?php
$con = mysql_connect("localhost","username","password");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("cbd", $con);

$result = mysql_query("SELECT date,ip,  count(ip) as count FROM syn_number WHERE date like '%05-08%' group by ip order by count desc limit 10");

echo "<table border='1'>

<tr>
<th>date</th>
<th>ip</th>
<th>number</th>
</tr>";
while($row = mysql_fetch_array($result))
  {
  echo "<tr>";
  echo "<td>" . $row['FirstName'] . "</td>";
  echo "<td>" . $row['LastName'] . "</td>";
  echo "</tr>";
  }
echo "</table>";
mysql_close($con);
?>

现在想把这段代码sql语句中的 05-08 和最后的limit 10 数字10 改为用表单提交，每次我可以输入
0508最好是可以输入一个范围比如0508到0510 这样

请问该如何实现？

用表单的话是要再搞个html文件了？

------解决方案--------------------
$limit = ' LIMIT ' . $_POST['start'] . ',' . $_POST['end'];

$sql = "SELECT date,ip, count(ip) as count FROM syn_number WHERE date like '%05-08%' group by ip order by count desc $limit";

$result = mysql_query($sql);
-----------

html

Limit:
<input type="text" name="start" />
<input type="text" name="end" />
------解决方案--------------------
SELECT date,ip, count(ip) as count FROM syn_number
你从数据只获得三列数据 date, ip, count 哪来的FirstName，SecondName，LastName？