回到两个数组的交集 _PHP

返回两个数组的交集
A数组

PHP code


array(
    [0] =>
        array(

        ['action_id'] =>
        3
        )
    [1] =>
        array(

        ['action_id'] =>
        2
    )
    [2] =>
        array(

        ['action_id'] =>
        1
    )
    [3] =>
        array(

        ['action_id'] =>
        7
    )
    [4] =>
        array(

        ['action_id'] =>
        11
    )
)

B数组：

PHP code


array(
    [0] =>
    array(

    ['action_id'] =>
    3
        ['type'] =>
        0
        ['order_num'] =>
        67
    )
    [1] =>
    array(

    ['action_id'] =>
    2
        ['type'] =>
        0
        ['order_num'] =>
        66
    )
    [2] =>
    array(

    ['action_id'] =>
    1
        ['type'] =>
        0
        ['order_num'] =>
        65
    )
    [3] =>
    array(

    ['action_id'] =>
    7
        ['type'] =>
        0
        ['order_num'] =>
        64
        )
    [8] =>
    array(

    ['action_id'] =>
    14
        ['type'] =>
        0
        ['order_num'] =>
        40
        )
    [13] =>
    array(

    ['action_id'] =>
    11
        ['type'] =>
        0
        ['order_num'] =>
        30
    )
)

使用array_intersect_key返回的为什么是

PHP code


array(
    [0] =>
    array(

    ['action_id'] =>
    3
        ['type'] =>
        0
        ['order_num'] =>
        67
    )
    [1] =>
    array(

    ['action_id'] =>
    2
        ['type'] =>
        0
        ['order_num'] =>
        66
    )
    [2] =>
    array(

    ['action_id'] =>
    1
        ['type'] =>
        0
        ['order_num'] =>
        65
    )
    [3] =>
    array(

    ['action_id'] =>
    7
        ['type'] =>
        0
        ['order_num'] =>
        64
        )
    
)

action_id为11的为什么没了？？

------解决方案--------------------

PHP code

$a = array(
  0 => array('action_id' => 3),
  1 => array('action_id' => 2),
  2 => array('action_id' => 1),
  3 => array('action_id' => 7),
  4 => array('action_id' => 11),
);

$b = array(
  0 => array('action_id' => 3, 'type' => 0, 'order_num' => 67),
  1 => array('action_id' => 2, 'type' => 0, 'order_num' => 66),
  2 => array('action_id' => 1, 'type' => 0, 'order_num' => 65),
  3 => array('action_id' => 7, 'type' => 0, 'order_num' => 64),
  8 => array('action_id' => 14, 'type' => 0, 'order_num' => 40),
  13 => array('action_id' => 11, 'type' => 0, 'order_num' => 30),
);

foreach($a as $v) $dict[] = $v['action_id'];
foreach($b as $k=>$v) if(in_array($v['action_id'], $dict)) $c[$k] = $v;
print_r($c);