代码如下:
<?php
/*
* Created on 2012-1-1
*
* To change the template for this generated file go to
* Window - Preferences - PHPeclipse - PHP - Code Templates
*/
$conn = mysql_connect("localhost","root","") or die ("连接出错");
mysql_select_db("dongxinb",$conn);
$sql="SELECT * FROM 'word'";
$query=mysql_query($sql,$conn);
$row=mysql_fetch_array($query);
echo $row[name];
?>
其中name为dongxinb数据库word表的字段。
错误信息:Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in D:\wamp\www\word\1.php on line 13
其中INSERT能正常插入。
------解决方案--------------------
SQL 错了
修改成
$sql="SELECT * FROM word";
------解决方案--------------------
- PHP code
<?php /* * Created on 2012-1-1 To change the template for this generated file go to * Window - Preferences - PHPeclipse - PHP - Code Templates */ include ("conn.php"); ?> <table width=500 border="0" align="center" cellpadding="5" cellspacing="1" bgcolor="#add3ef"> <?php $sql = "select * from word"; $query = mysql_query ( $sql ); while ( $row = mysql_fetch_array ( $query ) ) { echo <<<html <tr bgcolor="#eff3ff"> <td>姓名:{$row['name']}</td> </tr> <tr bgColor="#ffffff"> <td>Message:{$row['words']}</td> <td>更新时间:{$row['date']}</td> </tr> html; } ?> </table>