刚学PB，请大家看看什么问题
string is_name,is_pwd,pwd2,is_power
is_name=sle_1.text
is_pwd=sle_2.text
if is_name="" then
messagebox("","请选择用户名!")
sle_1.text=""
sle_1.setfocus()
else
if is_pwd="" then
messagebox("","请输入密码!")
sle_2.text=""
sle_2.setfocus()
else
select pwd into :pwd2 from user where id=:is_name;
if pwd2=is_pwd then
open(dw_main)
close(parent)
else
messagebox("","密码错误!")
sle_2.text=""
sle_2.setfocus()
end if
end if
end if
提示错误：syntax error or access violation：near 'user' from [user] where id=''
------解决方案--------------------
syntax error or access violation
语法错误或者访问冲突，看你数据库的表，user是不能做表名的