ls_qs = sle_1.text
ls_zz = sle_2.text
if ls_qs<>'' and ls_zz <>'' then
is_newselect = is_newselect + " and " + "a.sxhh = '" + ls_sxhh + "'"
end if
sxhh是字符型 如何进行比较
例如 sle_1.text ='0000001' sle_2.text = '9999999'
如何得出sxhh中没有在sle_1和sle_2范围内的字符???
比如sxhh只保存了0000001-0000010 能够得出之间没有的数???
------解决方案--------------------