date ld_today
ld_today = today()
在使用 Insert into test ( datesj ) value (:ld_today);
在写入后数表内列显示的内容为 12-12-13 00:00:00.000
后面的时间全部是00:00:00.000
求解!
------解决方案--------------------
datetime ld_today
ld_today = datetime(today(),now())
Insert into test ( datesj ) value (:ld_today);