题目描述
Give you two numbers a and b,how to know the a^b's the last digit number.It looks so easy,but everybody is too lazy to slove this problem,so they remit to you who is wise.输入There are mutiple test cases. Each test cases consists of two numbers a and b(0<=a,b<2^30)输出For each test case, you should output the a^b's last digit number.样例输入
7 66 8 800样例输出
9 6提示
There is no such case in which a = 0 && b = 0。
#include<iostream>
#include<algorithm>
using namespace std;
struct Node{int v, w;
}a[15];
bool cmp(Node a, Node b){return a.v > b.v;
}
int main()
{int n;cin >> n;while(n--){int s, m;cin >> s >> m;for (int i = 0; i < s; i++){cin >> a[i].v >> a[i].w;}sort(a, a + s, cmp);int ans = 0;for (int i = 0; i < s; i++){if(a[i].w > m){ans += m * a[i].v;break;}else{ans += a[i].w * a[i].v;m -= a[i].w;}}cout << ans << endl;}
}