分析：这里写链接内容
#include<iostream>
#include<algorithm>
#include<cmath>
using namespace std;
typedef long long ll;
int n,x;
bool flag=false;
int main(){ios::sync_with_stdio(false);cin>>x;//int t=(sqrt(1+8*x)-1)/2+100;int t=(sqrt(2*x));for(int n=t;n>=2;n--){if((2*x-(n-1)*n)%(2*n)==0 &&n*n+n<=2*x){flag=true;cout<<(2*x-(n-1)*n)/(2*n)<<endl;}}if(!flag){cout<<"No Solution"<<endl;}return 0;
}