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POJ - 3624 Charm Bracelet (0-1背包)

热度:100   发布时间:2023-11-04 05:34:08.0

题目链接 https://vjudge.net/problem/POJ-3624

题目

Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weight Wi (1 ≤ Wi ≤ 400), a 'desirability' factor Di (1 ≤ Di ≤ 100), and can be used at most once. Bessie can only support a charm bracelet whose weight is no more than M (1 ≤ M ≤ 12,880).

Given that weight limit as a constraint and a list of the charms with their weights and desirability rating, deduce the maximum possible sum of ratings.

Input

* Line 1: Two space-separated integers: N and M
* Lines 2..N+1: Line i+1 describes charm i with two space-separated integers: Wi and Di

Output

* Line 1: A single integer that is the greatest sum of charm desirabilities that can be achieved given the weight constraints

Sample Input

4 6
1 4
2 6
3 12
2 7

Sample Output

23

AC代码

#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
int s1[20000],s2[20000],dp[20000];
int main()
{int n,m;while(cin>>n>>m){for(int i=1;i<=n;i++)scanf("%d%d",&s1[i],&s2[i]);memset(dp,0,sizeof(dp));for(int i=1;i<=n;i++)for(int j=m;j>=s1[i];j--){dp[j]=max(dp[j-s1[i]]+s2[i],dp[j]);}cout<<dp[m]<<endl;}return 0;
}