- 绝对值排序
http://acm.hdu.edu.cn/showproblem.php?pid=2020
#include <stdio.h>
#include <math.h>
int main()
{
int i,n,t;int a[100];while(~scanf("%d",&n)){
if(n==0) break;for(i=1;i<=n;i++){
scanf("%d",&a[i]);}for(i=1;i<n;i++)//排序for(int j=i+1;j<=n;j++)if(fabs(a[i])<fabs(a[j])){
t=a[i];a[i]=a[j];a[j]=t;}for (i=1;i<=n;i++){
if(i!=n) printf("%d ",a[i]);else printf("%d\n",a[i]);}}return 0;
}
- 发工资咯
http://acm.hdu.edu.cn/showproblem.php?pid=2021
#include<stdio.h>
int main()
{
int i,j,n,t,k,s[6]={
100,50,10,5,2,1};while(~scanf("%d",&n),n) //逗号表达式{
for(i=j=k=0;i<n;i++,j=0){
scanf("%d",&t);while(t){
if(t<s[j]) j++;else t-=s[j],k++;}}printf("%d\n",k);}return 0;
}
2022海选女主角
http://acm.hdu.edu.cn/showproblem.php?pid=2022
#include <math.h>
#include <stdio.h>int main(void)
{
int i, j;int n, m;int x, y;double a, t;while (scanf("%d%d", &n, &m) != EOF){
a = x = y = 0;for (i = 0 ; i < n ; i++){
for (j = 0 ; j < m ; j++){
scanf("%lf", &t);if (fabs(t) > fabs(a)){
a = t;x = i;y = j;}}}printf("%d %d %.0f\n", x + 1, y + 1, a);}return 0;
}
2023求平均成绩
http://acm.hdu.edu.cn/showproblem.php?pid=2023
#include<stdio.h>
int main(void)
{
double n, m, a, b;int i, j, A, B;double e[50][5];double f[5];while (scanf("%lf %lf", &n, &m) != EOF){
a = 0;b = 0;B = 0;for (i = 0; i < n; i++){
for (j = 0; j < m; j++){
scanf("%lf", &e[i][j]);}}for (j = 0; j < n; j++){
a = 0;for (i = 0; i < m; i++){
a += e[j][i];}if (j == 0){
printf("%.2f", a/m);}else{
printf(" %.2f", a/m);}}printf("\n");for (i = 0; i < m; i++){
b = 0;for (j = 0; j < n; j++){
b += e[j][i];}f[i] = b / n;if (i == 0){
printf("%.2f", f[i]);}else{
printf(" %.2f",f[i]);}}printf("\n");for (i = 0; i < n; i++){
A = 0;for (j = 0; j < m; j++){
if (e[i][j] >= f[j])A++;}if (A == m)B++;}printf("%d\n\n", B);}return 0;
}
2024.C语言合法标识符
http://acm.hdu.edu.cn/showproblem.php?pid=2024
#include <stdio.h>
#include <ctype.h>int main(void)
{
int n;scanf("%d", &n);getchar();while (n--) {
char c, flag = 1;c = getchar();if (!(isalpha(c) || c == '_'))flag = 0;while ((c = getchar()) != '\n') {
if (!(isalnum(c) || c == '_'))flag = 0;}printf("%s\n", flag ? "yes" : "no");}return 0;
}
- 查找最大元素`
http://acm.hdu.edu.cn/showproblem.php?pid=2025
#include<stdio.h>
#include<string.h>
int main()
{
char max,str[101];int len,i;while(~scanf("%s",str)){
len=strlen(str);max='a';for(i=0;i<=len-1;i++){
if(str[i]>max){
max=str[i];}}for(i=0;i<=len-1;i++){
printf("%c",str[i]);if(str[i]==max){
printf("(max)");}}printf("\n");}return 0;
}
- 首字母变大写
http://acm.hdu.edu.cn/showproblem.php?pid=2026
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
char a[105];int i,len;while(gets(a)!='\0'){
len=strlen(a);if(a[0]!=' ')a[0]=a[0]-32;for(i=1;i<len;i++){
if(a[i]!=' '&&a[i-1]==' '){
a[i]=a[i]-32;}}puts(a);}return 0;
}
- 统计元音
http://acm.hdu.edu.cn/showproblem.php?pid=2027
# include <stdio.h>
# include <string.h>int main()
{
int n, len;char s[150];while(scanf("%d", &n) != EOF && n != 0){
getchar();while(n--){
gets(s);int a_count = 0;int e_count = 0;int i_count = 0;int o_count = 0;int u_count = 0;len = strlen(s);for(int i=0;i < len; i++){
if(s[i] == 'a') a_count += 1;if(s[i] == 'e') e_count += 1;if(s[i] == 'i') i_count += 1;if(s[i] == 'o') o_count += 1;if(s[i] == 'u') u_count += 1;}printf("a:%d\n", a_count);printf("e:%d\n", e_count);printf("i:%d\n", i_count);printf("o:%d\n", o_count);printf("u:%d\n", u_count);if(n) printf("\n");}}return 0;
}
- Lowest Common Multiple Plus(最小公倍数)
http://acm.hdu.edu.cn/showproblem.php?pid=2028
//最小公倍数 = 两整数 / 最大公约数
#include <stdio.h>
int gcd(int a,int b)
{
return b==0?a:gcd(b,a%b);
}
int lcm(int a,int b)
{
return a*b/gcd(a,b);
}
int main()
{
int a[100],n;while(scanf("%d",&n)==1){
int i,y=1;for(i=0;i<n;i++)scanf("%d",&a[i]);//转换成两个比较,比较n-1轮for(i=0;i<n-1;i++){
a[i+1]=lcm(a[i],a[i+1]);}printf("%d\n",a[i]);}return 0;
}
- Palindromes _easy version(回文串)
http://acm.hdu.edu.cn/showproblem.php?pid=2029
#include <stdio.h>
#include <string.h>int main(void)
{
int n, flag, start, end;char a[4096];scanf("%d", &n);while(n--) {
// 读入字符串scanf("%s", a);// 判断是否为回文start = 0;end = strlen(a) - 1;flag = 1;while(start < end) {
if(a[end] != a[start]) {
flag = 0;break;}start++;end--;}// 输出结果if(flag)printf("yes\n");elseprintf("no\n");}return 0;
}