Java - PAT - 1022. D进制的A+B (20)

题目链接：1022. D进制的A+B (20)

思路：

将十进制数转换成n进制数  ，1<n<=10  ，如果笔算就是把这个十进制数一直除，知道商是0，那么余数的倒序就是n进制数。这里的除即”/“去整，余数即”%“取余；

import java.util.Scanner;  
public class Main{  public static void main(String[] args){  Scanner sc = new Scanner(System.in);long a = sc.nextLong();long b = sc.nextLong();long d = sc.nextLong();long c  = a+b;StringBuilder str = (f(c,d));for(int i= str.length()-1 ;i>=0;i--){System.out.print(str.charAt(i));}System.out.println();}public static StringBuilder f(long a,long d){StringBuilder str = new StringBuilder();while(a/d!=0){str.append(a%d);a = a/d;}str.append(a%d);return str;}
}