PAT甲级-1028 List Sorting (25分)

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题目：
Excel can sort records according to any column. Now you are supposed to imitate this function.

Input Specification:
Each input file contains one test case. For each case, the first line contains two integers N (≤10^?5?? ) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student’s record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).

Output Specification:
For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID’s; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID’s in increasing order.

Sample Input 1:

3 1
000007 James 85
000010 Amy 90
000001 Zoe 60

Sample Output 1:

000001 Zoe 60
000007 James 85
000010 Amy 90

Sample Input 2:

4 2
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 98

Sample Output 2:

000010 Amy 90
000002 James 98
000007 James 85
000001 Zoe 60

Sample Input 3:

4 3
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 90

Sample Output 3:

000001 Zoe 60
000007 James 85
000002 James 90
000010 Amy 90

题意：
题目不难，就是N个学生，三种排序方式输出

注意： 如果用for(int i=0;i<N;i++)最后一个case超时，用for(auto it:all)就不会

我的代码：

#include<bits/stdc++.h>
using namespace std;class Stu
{
    
public:Stu(int id,string name,int score):id_(id),name_(name),score_(score){
    }int id_,score_;string name_;
};bool cmp1(Stu a,Stu b){
    return a.id_<b.id_;
}
bool cmp2(Stu a,Stu b){
    if(a.name_!=b.name_)return a.name_<b.name_;else return a.id_<b.id_;
}
bool cmp3(Stu a,Stu b){
    if(a.score_!=b.score_)return a.score_<b.score_;else return a.id_<b.id_;
}int main()
{
    int N,c;cin>>N>>c;vector<Stu>all;for(int i=0;i<N;i++){
    int id,sc;string name;cin>>id>>name>>sc;Stu t(id,name,sc);all.push_back(t);}if(c==1)sort(all.begin(),all.end(),cmp1);else if(c==2)sort(all.begin(),all.end(),cmp2);else sort(all.begin(),all.end(),cmp3);for(auto it:all){
    printf("%06d ",it.id_);cout<<it.name_<<" "<<it.score_<<endl;}return 0;
}