applicationContext.xml位置 路径出错class path resource [applicationContext.xml] cannot be opened

我是基于maven搭建的webapp项目

错误提示：

Caused by: java.io.FileNotFoundException: class path resource [applicationContext.xml] cannot be opened because it does not exist
    at org.springframework.core.io.ClassPathResource.getInputStream(ClassPathResource.java:172)
    at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:330)
    ... 13 more

解决方法：

一、把配置文件放到src/main/resources下面

下面三种配置都不行，原因是：用maven构建项目时候resource目录就是默认的classpath

下面在web.xml中配置方法无效，加载配置文件默认 就是WEB-INF/

<!-- 此方法配置无效 classpath:无法访问到WEB-INF下-->
<context-param>

<param-name>contextConfigLocation</param-name>

<param-value>classpath:applicationContext.xml</param-value>

</context-param>

<!-- 此方法配置无效 -->

<context-param>

<param-name>contextConfigLocation</param-name>

<param-value>classpath*:applicationContext.xml</param-value>

</context-param>

<!--此方法也不行 -->
<context-param><param-name>contextConfigLocation</param-name><param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>

二、加载的时候使用绝对路径定位

同理用FileSystemXmlApplicationContext也可以

ApplicationContext context = new ClassPathXmlApplicationContext("file:/Users/yourname/Desktop/myspring/src/main/webapp/WEB-INF/applicationContext.xml");