Triangular Sums
时间限制:
3000 ms | 内存限制:
65535 KB
难度:
2
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描述
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The nth Triangular number, T(n) = 1 + … + n, is the sum of the first n integers. It is the number of points in a triangular array withn points on side. For example T(4):
X
X X
X X X
X X X X
Write a program to compute the weighted sum of triangular numbers:
W(n) =
SUM[k = 1…n;k * T(k + 1)]
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输入
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The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.
Each dataset consists of a single line of input containing a single integer n, (1 ≤ n ≤300), which is the number of points on a side of the triangle. 输出
- For each dataset, output on a single line the dataset number (1 through N), a blank, the value of n for the dataset, a blank, and the weighted sum ,W(n), of triangular numbers for n. 样例输入
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4 3 4 5 10
样例输出
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1 3 45 2 4 105 3 5 210 4 10 2145
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#include <stdio.h> int main() {int n,m,sign = 1;scanf("%d",&n);while(n--){scanf("%d",&m);int i,s = 0;for(i = 1; i <= m; i++){s += i*((i+1)*(i+2)/2);}printf("%d %d %d\n",sign++,m,s);} }
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The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.