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POJ1905 Expanding Rods(二分)

热度:20   发布时间:2024-01-16 13:51:04.0

题意:

给一个长度为L的钢条,加热后长度改变并且弯曲成一个弧,算出之间的距离

要点:

基础思想是二分,但其实里面包含了很多证明

参考博客:点击打开链接


15301383 Seasonal 1905 Accepted 196K 0MS C++ 510B 2016-03-22 20:56:20
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<math.h>
double l, n, c,L;
double r;double depart(double left, double right)
{double h, r, ll;while (right-left>0.000001)//精确度6位{h = (left + right) / 2.0;r = (4 * h*h + l*l) / (8 * h);ll = 2 * r*asin(l / (2 * r));if (ll > L)right = h;elseleft = h;}return h;
}int main()
{while (~scanf("%lf%lf%lf", &l, &n, &c)){if (l == -1)break;L = l*(1 + n*c);printf("%.3lf\n", depart(0, l / 2.0));}return 0;
}