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Codeforces Round #523 (Div. 2)A. Coins 水题

热度:51   发布时间:2024-01-15 07:17:59.0

A. Coins

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

You have unlimited number of coins with values 1,2,…,n1,2,…,n. You want to select some set of coins having the total value of SS.

It is allowed to have multiple coins with the same value in the set. What is the minimum number of coins required to get sum SS?

Input

The only line of the input contains two integers nn and SS (1≤n≤1000001≤n≤100000, 1≤S≤1091≤S≤109)

Output

Print exactly one integer — the minimum number of coins required to obtain sum SS.

Examples

input

Copy

5 11

output

Copy

3

input

Copy

6 16

output

Copy

3

Note

In the first example, some of the possible ways to get sum 1111 with 33 coins are:

  • (3,4,4)(3,4,4)
  • (2,4,5)(2,4,5)
  • (1,5,5)(1,5,5)
  • (3,3,5)(3,3,5)

It is impossible to get sum 1111 with less than 33 coins.

In the second example, some of the possible ways to get sum 1616 with 33 coins are:

  • (5,5,6)(5,5,6)
  • (4,6,6)(4,6,6)

It is impossible to get sum 1616 with less than 33 coins.

#include<cstdio>
#include<iostream>
#include<fstream>
#include<algorithm>
#include<functional>
#include<cstring>
#include<string>
#include<cstdlib>
#include<iomanip>
#include<numeric>
#include<cctype>
#include<cmath>
#include<ctime>
#include<queue>
#include<stack>
#include<list>
#include<set>
#include<map>
using namespace std;
#define N 100+5
#define MAX 26
typedef long long ll;
ll n,m;
ll a[N];
int main()
{//string s;//cin>>s;ll ans=0;scanf("%I64d%I64d",&n,&m);ans=m/n;if(ans*n<m)ans++;printf("%I64d",ans);/*for(int i=1;i<=n;i++){printf("%I64d ",a[i]);} */return 0;
}

 

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