1、http://acm.nbut.edu.cn/Problem/view.xhtml?id=1543
2、题目大意
情人节将至,有n个人分别跟自己喜欢的人约会,给出每个人约会的人编号,如果带走其中一个人,那么喜欢这个人的那些人将会不开心,现在你要带走一个人,使得不开心的人数最多
简单题,不过太心急了,没有注意好边界就提交,导致wrong了两遍才AC
3、题目:
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[C] No Girlfriend
- 时间限制: 2000 ms 内存限制: 262144 K
- 问题描述
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You know the day after tomorrow is Valentine's Day, but I have no girlfriend.
Now, I'll give you a big task, help me take away a person!
If you take away that person, others who want to appointment with him/her will feel disappointed.
Your task is to let maximum people feel disappointed.
- 输入
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There are multiple test cases, each test case contain a positive number N (1 <= N <= 100).
Following N lines, for the ith line (1-Based) contain a positive integer P (1 <= P <= N), represent the ith people want to appointment with P.
Note: Everyone has a distinct number, the ith people's number is i.
- 输出
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For each case, output the answer in one line.
- 样例输入
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3311555222
- 样例输出
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23
- 提示
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For the first test case.If you take away 1, then 2 and 3 will feel disappointed.If you take away 2, nobody will feel disappointed.If you take away 3, then 1 will feel disappointed.So the maximum people feel disappointed is 2.
4、AC代码:
#include<stdio.h> #include<string.h> #include<algorithm> using namespace std; int b[105]; int cmp(int c,int d) {return c>d; } int main() {int n,a;while(scanf("%d",&n)!=EOF){memset(b,0,sizeof(b));for(int i=0;i<n;i++){scanf("%d",&a);b[a]++;}sort(b,b+n+1,cmp);printf("%d\n",b[0]);}return 0; }