[J] Dumb Typo(题目很简单，比赛错在不该自己计算，应该用电脑跑一遍的)

1、http://acm.nbut.edu.cn/Problem/view.xhtml?id=1550

2、题目

• [J] Dumb Typo

• 时间限制: 2000 ms　内存限制: 262144 K       

• 问题描述
• Hello everyone who is partcipate in the Fighting For 2014 Contest, I'm MatRush. This is the simplest problem today, no algorithm knowledge needed, But it's also the hardest problem today if you are not on the right track, so please do not waste your time here if you have no idea with it after many tries.
  I was writing some C++ code one day, and I typed this fragment:
  
  x = y * 2 + 1;
  
  But unfortunately I had a bug. When y was 10, I wanted x to be 19. To fix this, I changed the '+' to a '-'.
  After fixing this bug, I wrote some more code:
  
  x = y * 2245 + (y * 2 - 7);
  
  I had a another bug. When y was 79, I wanted x to be 8841. What single character can I change to make this work? Remember your first answer as "pos,new char". For example, the answer to the first bug would be "10,-": we're changing the 10th (start from 0th) character ('+') to '-'.
  Several days later.
  I can't believe I made the same mistake again! Still this childish and straightforward code.
  
  x = y * 2245 + (y * 2 - 7);
  
  This time I had an another different bug. When y was 79, I wanted x to be 13186. What single character can I change to make this work? Remember your second answer as "pos,new char". For example, the answer to the first bug would be "10,-": we're changing the 10th (start from 0th) character ('+') to '-'.
  
• 输入
• There is no input           
• 输出
• Please submit your two answer in separate lines (two lines).
  
• 样例输入

• There is no input

• 样例输出

• Sorry, no sample output.
  But I give you a wrong output for sample format. Here it is.
  1,-
  2,+
  

   

  3、AC代码：

  #include<stdio.h>
  #include<string.h>
  #include<algorithm>
  using namespace std;
  char s[100];
  int main()
  {printf("10,*\n");printf("8,0\n");return 0;
  }