A Tale from the Dark Side of The Moon
Time Limit: 1000MS Memory limit: 65536K
题目描述
Us: So why don’t you just recompile the program Us: What about "ddd" and "dddd"? How does it on the new hardware? behave then?
Them: We cannot. We lost the source code. Them: Where in English will you find a "dddd" or even a "ddd"? Haven’t you been listening?
Us: How typical! What does the program do? Do you have any documentation?
Them: The manual page does mention something about the documentation in the source code.
Us: A manual page is good. What does it say?
Them: Just one line: “See the source code for more information.”
Us: Argh! What do you know about the program?
Them: Well, it seems to be taking simple text, similar to that found in an English dictionary, and printing it after some modification.
Us: What kind of modification?
Them: It removes any character that is not a lowercase letter. But not white spaces. White spaces are preserved as seen in the input.
Us: Do you have a sample input/output?
Them: Plenty. Here’s one. (see next page.)
Us: This is rather small! Did you try it on anything
bigger?
Us: Oops. We’ll pay more attention. Anything else?
Another one of them: There is also the "vv" thingy.
Us: What about "vv"?
Them: Every "vv" is replaced with a "m".Yet another one of them: No, wait! That was a printer problem. it had nothing to do with the program.
Remember?
Them: Oh, that’s right.thingy. Forget about the "vv"
Us: What about the "dd" thingy? Was that just a printer problem too?
Them: No. That was the program.
Us: What else?
Them: One last thing.every "ei" with "ie".It seems to be replacing
Us: Every one of them?
Them: Except if it comes right after "c" then it remains as is.
Them: It works on any text as long as the lines are Them: No, we just remembered one more thing: It less then eighty characters wide. It doesn’t seem replaces the sequence "pink" with "floyd" any to mind working on lengthy documents. But it where in the text.does terminate once it sees the sequence "EOF" (without the double quotes.)
One of them: Don’t forget to tell them about the Us: What?! Who wrote this program? Why do you "dd" thingy. need it in the first place?
Us: : What "dd" thingy?
Them: We think it will increase our chances of going to Banff in April 2008 if we get it right.
Them: We think it will increase our chances of going to Banff in April 2008 if we get it right.
Them: Whenever it sees a pair of small letter "d",one right after the other, it replaces them with "p".
Us: Makes sense. That’s all, right?
Us: Yeah! Right.
Us: Why?
Them: Who knows? It just does that!
输入
输出
示例输入
unpinked is an 8 letter word. Honest! vv is ok, d123d is ok, 123dd is not i received mail from liechtenstein.. ...adding means to imitat.#$!%%$e EOF
示例输出
unfloyded is an letter word onest vv is ok dd is ok p is not i received mail from liechtenstienaping means to imitate
代码：
#include <iostream>
#include <string>
using namespace std;
int main()
{while(true){string s1;string s2 = "";getline(cin, s1);int l = s1.length();bool flag = true;for (int i = 0; i < l; i++){char c = s1.at(i);if(i < l-1 && c == 'd' && s1.at(i+1) == 'd'){s2 += 'p';i++;}else if(i < l-1 && c == 'e' && s1.at(i+1) == 'i' && (i==0 || s1.at(i-1) != 'c')){s2 += "ie";i++;}else if(i < l-3 && c == 'p' && s1.at(i+1) == 'i' && s1.at(i+2) == 'n' && s1.at(i+3) == 'k'){s2 += "floyd";i += 3;}else if( i< l-2 && c== 'E' && s1.at(i+1) == 'O' && s1.at(i+2) == 'F'){flag = false;break;}else if(c >= 'a' && c <= 'z' || c== ' ')s2 += c;}cout<<s2<<endl;if (flag == false)break;}return 0;
}