这道题是一个让人做完觉得很爽的搜索题，可以用深搜也可以用宽搜。 相对来说，深搜的代码量稍微小一点。 搜索策略就是模拟倒来倒去的过程，并且出现重复的没有意义。
BFS版本： 我是人工写了个队列，这样比STL中的快一点
/*
ID: sdj22251
PROG: calfflac
LANG: C++
*/
#include <iostream>
#include <vector>
#include <list>
#include <map>
#include <set>
#include <deque>
#include <queue>
#include <stack>
#include <bitset>
#include <algorithm>
#include <functional>
#include <numeric>
#include <utility>
#include <sstream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <cctype>
#include <string>
#include <cstring>
#include <cmath>
#include <ctime>
#define MAX 2000000000
#define LOCA
#define M 1007
using namespace std;
int a, b, c;
bool can[M];
bool flag[M][M];
struct wwj
{int x, y, z;wwj(){}wwj(int xx, int yy, int zz){x = xx;y = yy;z = zz;}
}q[M * M];
void bfs(int x, int y, int z)
{int head = 0, tail = 0;wwj A(x, y, z);q[tail++] = A;flag[x][y] = true;if(A.x == 0) can[A.z] = true;while(head < tail){A = q[head++];if(A.x == 0) can[A.z] = true;if(A.x < a && A.z > 0){if(A.z > a - A.x && !flag[a][A.y]) {wwj B(a, A.y, A.z - a + A.x); flag[B.x][B.y] = true; q[tail++] = B;}if(A.z <= a - A.x && !flag[A.x + A.z][A.y]) {wwj B(A.x + A.z, A.y, 0); flag[B.x][B.y] = true; q[tail++] = B;}}if(A.y < b && A.x > 0){if(A.x > b - A.y && !flag[A.x + A.y - b][b]) {wwj B(A.x + A.y - b, b, A.z); flag[B.x][B.y] = true; q[tail++] = B;}if(A.x <= b - A.y && !flag[0][A.x + A.y]) {wwj B(0, A.x + A.y, A.z); flag[B.x][B.y] = true; q[tail++] = B;}}if(A.z < c && A.y > 0){if(A.y > c - A.z && !flag[A.x][A.y + A.z - c]) {wwj B(A.x, A.y + A.z - c, c); flag[B.x][B.y] = true; q[tail++] = B;}if(A.y <= c - A.z && !flag[A.x][0]) {wwj B(A.x, 0, A.z + A.y); flag[B.x][B.y] = true; q[tail++] = B;}}if(A.x > 0 && A.z < c){if(A.x > c - A.z && !flag[A.x + A.z - c][A.y]) {wwj B(A.x + A.z - c, A.y, c);flag[B.x][B.y] = true; q[tail++] = B;}if(A.x <= c - A.z && !flag[0][A.y]) {wwj B(0, A.y, A.z + A.x);flag[B.x][B.y] = true; q[tail++] = B;}}if(A.y > 0 && A.x < a){if(A.y > a - A.x && !flag[a][A.y + A.x - a]) {wwj B(a, A.y + A.x - a, A.z);flag[B.x][B.y] = true; q[tail++] = B;}if(A.y <= a - A.x && !flag[A.x + A.y][0]) {wwj B(A.x + A.y, 0, A.z);flag[B.x][B.y] = true; q[tail++] = B;}}if(A.z > 0 && A.y < b){if(A.z > b - A.y && !flag[A.x][b]) {wwj B(A.x, b, A.z + A.y - b);flag[B.x][B.y] = true; q[tail++] = B;}if(A.z <= b - A.y && !flag[A.x][A.y + A.z]) {wwj B(A.x, A.y + A.z, 0);flag[B.x][B.y] = true; q[tail++] = B;}}}
}
int main()
{
#ifdef LOCALfreopen("calfflac.in","r",stdin);freopen("calfflac.out","w",stdout);
#endifint i;scanf("%d%d%d", &a, &b, &c);bfs(0, 0, c);for(i = 0; i <= c; i++)if(can[i])printf("%d ", i);printf("\n");return 0;
}/*
ID: sdj22251
PROG: calfflac
LANG: C++
*/
#include <iostream>
#include <vector>
#include <list>
#include <map>
#include <set>
#include <deque>
#include <queue>
#include <stack>
#include <bitset>
#include <algorithm>
#include <functional>
#include <numeric>
#include <utility>
#include <sstream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <cctype>
#include <string>
#include <cstring>
#include <cmath>
#include <ctime>
#define MAX 2000000000
#define LOCA
#define M 1007
using namespace std;
int a, b, c;
bool can[M];
bool flag[M][M];
void dfs(int x, int y, int z)
{if(flag[x][y]) return;flag[x][y] = true;if(x == 0) can[z] = true;if(x < a && z > 0){if(z > a - x) dfs(a, y, z - a + x);if(z <= a - x) dfs(x + z, y, 0);}if(y < b && x > 0){if(x > b - y) dfs(x + y - b, b, z);if(x <= b - y) dfs(0, x + y, z);}if(z < c && y > 0){if(y > c - z) dfs(x, y + z - c, c);if(y <= c - z) dfs(x, 0, z + y);}if(x > 0 && z < c){if(x > c - z) dfs(x + z - c, y, c);if(x <= c - z) dfs(0, y, z + x);}if(y > 0 && x < a){if(y > a - x) dfs(a, y + x - a, z);if(y <= a - x) dfs(x + y, 0, z);}if(z > 0 && y < b){if(z > b - y) dfs(x, b, z + y - b);if(z <= b - y) dfs(x, y + z, 0);}
}
int main()
{
#ifdef LOCALfreopen("calfflac.in","r",stdin);freopen("calfflac.out","w",stdout);
#endifint i;scanf("%d%d%d", &a, &b, &c);dfs(0, 0, c);for(i = 0; i <= c; i++)if(can[i])printf("%d ", i);printf("\n");return 0;
}