题意需要注意的一点就是，
序列是从外层最小的那个位置顺时针转一圈得来的。并且要求10在内圈
所以，这题暴力的话，假定最上面那个点一定是第一个点，算下和更新下就行。
#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>
#include <cstdlib>
#include <ctime>
#include <set>
#include <vector>
#include <map>
#define MAXN 111
#define MAXM 55555
#define INF 1000000007
using namespace std;
int a[12];
int sum[6];
string ans, tmp;
int main()
{int n = 10;int first = 1;ans = "", tmp = "";for(int i = 1; i <= n; i++) a[i] = i;do {int pos = 1;for(int i = 1; i <= 5; i++) {if(a[i] < a[pos]) pos = i;int z = i + 6;if(z > 10) z = z - 5;sum[i] = a[i] + a[i + 5] + a[z];}if(pos != 1) continue;int flag = 1;for(int i = 2; i <= 5; i++)if(sum[i] != sum[i - 1]) flag = 0;if(sum[1] != sum[5]) flag = 0;for(int i = 6; i <= 10; i++) {if(a[i] == 10) flag = 0;}tmp = "";if(flag) {for(int i = 1; i <= 5; i++) {int z = i + 6;if(z > 10) z = z - 5;tmp += (a[i] + 'a');tmp += (a[i + 5] + 'a');tmp += (a[z] + 'a');}if(!first) {if(ans < tmp) ans = tmp;} else {ans = tmp;first = 1;}}}while(next_permutation(a + 1, a + n + 1));for(int i = 0; i < 15; i++) printf("%d", ans[i] - 'a');return 0;
}