JAXB: 使用JAXB标注POJO，进行XML转换

1. 编写简单的POJO，并添加基本的注解，类似于JPA，只有被@XmlRootElement标注的类才会处理：

package org.jack.jaxb;import javax.xml.bind.annotation.XmlRootElement;/** @author 李文锴*/@XmlRootElementpublic class Jack {private String firstName;private String lastName;public String getFirstName() {return firstName;}public void setFirstName(String firstName) {this.firstName = firstName;}public String getLastName() {return lastName;}public void setLastName(String lastName) {this.lastName = lastName;}}

2. 编写测试类，进行POJO与XML的转换：

package org.jack.jaxb;import java.io.StringReader; import java.io.StringWriter;import javax.xml.bind.JAXBContext; import javax.xml.bind.Marshaller; import javax.xml.bind.Unmarshaller;public class JAXBTest {public static void main(String[] args) throws Exception {JAXBContext context = JAXBContext.newInstance(Jack.class);Marshaller marshaller = context.createMarshaller();Unmarshaller unmarshaller = context.createUnmarshaller();Jack jack = new Jack();jack.setFirstName("jack");jack.setLastName("lee");StringWriter writer = new StringWriter();marshaller.marshal(jack, writer);System.out.println(writer.toString());String xml = "<jack><firstName>first</firstName><lastName>last</lastName></jack>";Jack xj = (Jack) unmarshaller.unmarshal(new StringReader(xml));System.out.println(xj.getFirstName());System.out.println(xj.getLastName());}}

3. 查看输出结果：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?><jack><firstName>jack</firstName><lastName>lee</lastName></jack> first last