Description
Bessie has gone to the mall’s jewelry store and spies a charm bracelet. Of course, she’d like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weight Wi (1 ≤ Wi ≤ 400), a ‘desirability’ factor Di (1 ≤ Di ≤ 100), and can be used at most once. Bessie can only support a charm bracelet whose weight is no more than M (1 ≤ M ≤ 12,880).
Given that weight limit as a constraint and a list of the charms with their weights and desirability rating, deduce the maximum possible sum of ratings.
Input
- Line 1: Two space-separated integers: N and M
- Lines 2..N+1: Line i+1 describes charm i with two space-separated integers: Wi and Di
Output
- Line 1: A single integer that is the greatest sum of charm desirabilities that can be achieved given the weight constraints
Sample Input
4 6
1 4
2 6
3 12
2 7
Sample Output
23
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
int main()
{int n,m;scanf("%d%d",&n,&m);int a[5005],w[5005],dp[12885];memset(dp,0,sizeof(dp));for(int i = 0;i < n;i ++)scanf("%d%d",&a[i],&w[i]);for(int i = 0;i < n;i ++)for(int j = m;j>=a[i];j --)dp[j]=max(dp[j],dp[j-a[i]]+w[i]);printf("%d\n",dp[m]);return 0;
}