传送门
题意：给你一个矩阵范围和 n 个人的 t 个位置，让你判断有多少人进入过这个矩阵，又有多少人连续 k 个位置一直处于矩阵内。直接遍历统计一下即可，注意逗留的人也算经过。
代码实现：
import java.util.*;public class Main {public static void main(String[] args) {Scanner in = new Scanner(System.in);int n = in.nextInt();int k = in.nextInt();int t = in.nextInt();int [] f = new int[10];for(int i = 1; i <= 4; i ++)f[i] = in.nextInt();int ans_j = 0, ans_d = 0, w = 0;while(n-->0){int tmp = 0, dl = 0, jg = 0;for(int i = 1; i <= t; i ++){int a = in.nextInt();int b = in.nextInt();if(f[1]<=a&&a<=f[3] && f[2]<=b&&b<=f[4]) {jg = 1;tmp ++;if(k<=tmp) dl = 1;}else tmp = 0;}ans_d += dl;ans_j += jg;}System.out.println(ans_j);System.out.println(ans_d);in.close();}
}