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mysql GRANT with ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: NO

热度:50   发布时间:2023-12-19 16:33:05.0
mysql GRANT with  ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: NO)


问题现象:
mysql> GRANT ALL PRIVILEGES ON *.* TO 'lixora'@'%' ;
ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: NO)


问题重现及问题分析:
缺省使用 mysql 登入 mysql server:

[root@localhost ~]# mysql
Welcome to the MySQL monitor.  Commands end with ; or \g.
Your MySQL connection id is 4296
Server version: 5.6.28-log MySQL Community Server (GPL)
Copyright (c) 2000, 2015, Oracle and/or its affiliates. All rights reserved.
Oracle is a registered trademark of Oracle Corporation and/or its
affiliates. Other names may be trademarks of their respective
owners.

Type 'help;' or '\h' for help. Type '\c' to clear the current input statement.

----对lixora 用户授权 :
mysql> GRANT ALL PRIVILEGES ON *.* TO 'lixora'@'%' ;
ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: NO)
报错了显示用户'root'@'localhost' 没有使用密码


----查看下用户密码信息:
mysql> select host,user,password from mysql.user;
+--------------+--------+-------------------------------------------+
| host         | user   | password                                  |
+--------------+--------+-------------------------------------------+
| %            | root   | *E74858DB86EBA20BC33D0AECAE8A8108C56B17FA |
| lixora       | root   | *E74858DB86EBA20BC33D0AECAE8A8108C56B17FA |
| 127.0.0.1    | root   | *E74858DB86EBA20BC33D0AECAE8A8108C56B17FA |
| ::1          | root   | *E74858DB86EBA20BC33D0AECAE8A8108C56B17FA |
|              | root   |                                           |
| localhost    | zabbix | *DEEF4D7D88CD046ECA02A80393B7780A63E7E789 |
| localhost    | root   |                                           |
| %            | zabbix | *DEEF4D7D88CD046ECA02A80393B7780A63E7E789 |
| 10.80.18.237 | zabbix | *DEEF4D7D88CD046ECA02A80393B7780A63E7E789 |
| %            | lixora | *E74858DB86EBA20BC33D0AECAE8A8108C56B17FA |
+--------------+--------+-------------------------------------------+
10 rows in set (0.00 sec)

-----查看当前窗口用户信息
mysql> status
--------------
mysql  Ver 14.14 Distrib 5.6.28, for Linux (x86_64) using  EditLine wrapper


Connection id:          4296
Current database:
Current user:           root@localhost---------注意!!!
SSL:                    Not in use
Current pager:          stdout
Using outfile:          ''
Using delimiter:        ;
Server version:         5.6.28-log MySQL Community Server (GPL)
Protocol version:       10
Connection:             Localhost via UNIX socket
Server characterset:    latin1
Db     characterset:    latin1
Client characterset:    utf8
Conn.  characterset:    utf8
UNIX socket:            /var/lib/mysql/mysql.sock
Uptime:                 4 hours 16 min 12 sec


Threads: 26  Questions: 123774  Slow queries: 0  Opens: 193  Flush tables: 1  Open tables: 186  Queries per second avg: 8.051
--------------

mysql> select user(), current_user();
+----------------+----------------+
| user()         | current_user() |
+----------------+----------------+
| root@localhost | root@localhost |  --------注意!!!
+----------------+----------------+
1 row in set (0.00 sec)


mysql> show grants;
+--------------------------------------------------------------+
| Grants for root@localhost                                    |
+--------------------------------------------------------------+
| GRANT ALL PRIVILEGES ON *.* TO 'root'@'localhost'            |----好像少了点什么?
| GRANT PROXY ON ''@'' TO 'root'@'localhost' WITH GRANT OPTION |
+--------------------------------------------------------------+
2 rows in set (0.00 sec)

我们发现当前连接的用户为'root'@'localhost' ,且该用户的权限为【GRANT ALL PRIVILEGES ON *.* TO 'root'@'localhost' 】
到这里我想应该找到问题的源头了。。。。。
对,没错就是with grant option 权限;

关于with grant option 有 mysql reference的官方解释
WITH GRANT OPTION :clause gives the user the ability to give to other users any privileges the user has at the specified privilege leve


出现这个问题时会茫然,不能快速找到根本原因是没有理解懂mysql 的用户管理体系:
mysql 的用户不是一个简单的username 来唯一确定,一个真正的mysql user是 ‘username’@‘hostname’ 组合来唯一确定的;
也就是说 root@localhost \\  root@127.0.0.1 不是同一个用户是2个用户,且用户的权限也是完全独立的:


mysql>  show grants for 'root'@'localhost';
+--------------------------------------------------------------+
| Grants for root@localhost                                    |
+--------------------------------------------------------------+
| GRANT ALL PRIVILEGES ON *.* TO 'root'@'localhost'            |
| GRANT PROXY ON ''@'' TO 'root'@'localhost' WITH GRANT OPTION |
+--------------------------------------------------------------+
2 rows in set (0.00 sec)


mysql> show grants for 'root'@'127.0.0.1';
+---------------------------------------------------------------------------------------------------------------------------
| Grants for root@127.0.0.1                                                                                                |
+---------------------------------------------------------------------------------------------------------------------------
| GRANT ALL PRIVILEGES ON *.* TO 'root'@'127.0.0.1' IDENTIFIED BY PASSWORD '*E74858DB86EBA20BC33D0AECAE8A8108C56B17FA' WITH GRANT OPTION |
+---------------------------------------------------------------------------------------------------------------------------
1 row in set (0.00 sec)


这里清楚了吧。


----总结:
下次出现这个问题时,先看下当前是什么用户?


mysql> select current_user;
+----------------+
| current_user   |
+----------------+
| root@127.0.0.1 |
+----------------+
1 row in set (0.00 sec)

status 命令看到不一定是真的

看下当前用户权限;
show grants;


如果发现没有with grant 权限的;如果知道其他mysql root 用户密码可以使用 mysql -uroot -p -h127.0.0.1 登入;


如果实在不知道,也没关系,直接改mysql的 root 密码吧:
/etc/init.d/mysql stop
mysqld_safe --skip-grants-table &


--修改root用户密码
use mysql;
select host, user, password from user;
update mysql.user set password=password("mysql") where user="root" and host='127.0.0.1';


重启mysql
/etc/init.d/mysql stop
mysqld_safe &
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