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oracle dataguard 带宽评估

热度:51   发布时间:2023-12-19 16:21:11.0

--数据库层面理论估算:

select thread#,sequence#,blocks*block_size/1024/1024 MB,(next_time-first_time)*86400 sec, blocks*block_size/1024/1024/((next_time-first_time)*86400) "MB/s"
 from v$archived_log where ((next_time-first_time)*86400<>0) and first_time between  to_date('2015/01/15 08:00:00','YYYY/MM/DD HH24:MI:SS') and 
 to_date('2015/01/15 11:00:00','YYYY/MM/DD HH24:MI:SS') and dest_id=2 order by first_time;

  THREAD#  SEQUENCE#   MB   SEC MB/s 
---------- ---------- ---------- ---------- ---------- 
         2       2291 29366.1963        831  35.338383 
         1       2565 29365.6553        781 37.6000708 
         2       2292 29359.3403        537  54.672887 
         1       2566 29407.8296        813 36.1719921 
         2       2293 29389.7012        678 43.3476418 
         2       2294 29325.2217       1236 23.7259075 
         1       2567 11407.3379       2658 4.29169973 
         2       2295 29452.4648        477 61.7452093 
         2       2296 29359.4458        954 30.7751004 
         2       2297 29311.3638        586 50.0193921 
         1       2568 3867.44092       5510 .701894903
         
 使用oracle 工具 oratcptest 直接测试dg 和生产服务器间网络带宽是否满足        
---on server 
% java -jar oratcptest.jar -server -port=5555
On one of the primary hosts use oratcptest to connect to the server process on the standby host and transfer a fixed amount of data. 
 For example, if the Data Guard transport will be using ASYNC run a command similar to the following to determine the maximum  throughput the network will provide:


---on client:
$ java -jar oratcptest.jar slcc32adm07 -port=5555 -mode=async -duration=10s -interval=2s
[Requesting a test]
        Message payload        = 1 Mbyte
        Payload content type   = RANDOM
        Delay between messages = NO
        Number of connections  = 1
        Socket send buffer     = (system default)
        Transport mode         = ASYNC
        Disk write             = NO
        Statistics interval    = 2 seconds
        Test duration          = 10 seconds
        Test frequency         = NO
        Network Timeout        = NO
        (1 Mbyte = 1024x1024 bytes)

(08:08:03) The server is ready.
                        Throughput            
(08:08:05)              113.052 Mbytes/s
(08:08:07)              113.232 Mbytes/s
(08:08:09)              113.198 Mbytes/s
(08:08:11)              113.205 Mbytes/s
(08:08:13)              113.189 Mbytes/s
(08:08:13) Test finished.
               Socket send buffer = 528880 bytes
                  Avg. throughput = 113.140 Mbytes/s
                  
The above example shows that the avg. network throughput of 113MB/sec is sufficient to keep up with the database peak redo rate.  If the network throughput is not enough try adjusting the socket send and receive buffer sizes similar to the following:

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