文章作者:Tyan
博客:noahsnail.com | CSDN | 简书
1. 问题描述
Given a collection of distinct numbers, return all possible permutations.
For example, [1,2,3]
have the following permutations:
[[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]
]
2. 求解
递归法
这道题是求数组的全排列,首先可以用递归法,第一次往链表添加一个元素,有n中可能,然后将剩下的元素再添加一个元素到链表中,有n-1种可能,以此类推,直至链表中的元素大小等于数组大小。
public class Solution {
public static List<List<Integer>> result = new ArrayList<List<Integer>>();public List<List<Integer>> permute(int[] nums) {result.clear();permutation(nums, new ArrayList());return result;}public void permutation(int[] nums, List<Integer> list) {if(list.size() == nums.length) {result.add(list);return;}for(int i = 0; i < nums.length; i++) {if(!list.contains(nums[i])) {List<Integer> subList = new ArrayList<Integer>(list);subList.add(nums[i]);permutation(nums, subList);}}}
}