文章作者:Tyan
博客:noahsnail.com | CSDN | 简书
1. Description
2. Solution
**解析:**枚举所有可能情况,替换对应的?
即可。
- Version 1
class Solution:def maximumTime(self, time: str) -> str:result = ''if time[0] == '?':if time[1] < '4' or time[1] == '?':result += '2'else:result += '1'else:result += time[0]if time[1] == '?':result += '9' if result[-1] < '2' else '3'else:result += time[1]result += ':'result += '5' if time[3] == '?' else time[3]result += '9' if time[4] == '?' else time[4]return result
Reference
- https://leetcode.com/problems/latest-time-by-replacing-hidden-digits/