文章作者:Tyan
博客:noahsnail.com | CSDN | 简书
1. Description
2. Solution
**解析:**Version 1,统计行和和列和,然后逐个判断。
- Version 1
class Solution:def countServers(self, grid: List[List[int]]) -> int:m = len(grid)n = len(grid[0])# rowSum = [sum(grid[i]) for i in range(m)]# colSum = [sum(x) for x in zip(*grid)]rowSum = [0] * mcolSum = [0] * nfor i in range(m):for j in range(n):if grid[i][j] == 1:rowSum[i] += 1colSum[j] += 1count = 0for i in range(m):for j in range(n):if grid[i][j] == 1 and (rowSum[i] > 1 or colSum[j] > 1):count += 1return count
Reference
- https://leetcode.com/problems/count-servers-that-communicate/