文章作者:Tyan
博客:noahsnail.com | CSDN | 简书
1. Description
2. Solution
**解析:**Version 1,根据题意,需要先数组求和,然后再求跟目标的差值,为了添加最少数量的数字,因此每次都应添加极限数值,题目变成了算除法并对余数取整。
- Version 1
class Solution:def minElements(self, nums: List[int], limit: int, goal: int) -> int:total = sum(nums)diff = goal - totalcount = ceil(abs(diff) / limit)return count
Reference
- https://leetcode.com/problems/minimum-elements-to-add-to-form-a-given-sum/