文章作者:Tyan
博客:noahsnail.com | CSDN | 简书
1. Description
2. Solution
**解析:**Version 1,每次数组索引向右移动,相当于当前数字左移一位,因此当前数值应在上一数值的基础上乘以2
,加上当前位。
- Version 1
class Solution:def prefixesDivBy5(self, nums: List[int]) -> List[bool]:n = len(nums)pre = 0result = [0] * nfor i in range(n):current = pre * 2 + nums[i]#current = (pre << 1) + nums[i]result.append(current % 5 == 0)pre = currentreturn result
Reference
- https://leetcode.com/problems/binary-prefix-divisible-by-5/