文章作者:Tyan
博客:noahsnail.com | CSDN | 简书
1. Description
2. Solution
**解析:**Version 1,碰到0
直接返回0
,计数负数的个数,如果负数个数时奇数返回-1
,偶数返回1
。
- Version 1
class Solution:def arraySign(self, nums: List[int]) -> int:count = 0for num in nums:if num == 0:return 0elif num < 0:count += 1if count % 2 == 0:return 1else:return -1
- Version 2
class Solution:def arraySign(self, nums: List[int]) -> int:result = 1for num in nums:if num == 0:return 0elif num < 0:result *= -1return result
Reference
- https://leetcode.com/problems/sign-of-the-product-of-an-array/