题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=2057
Problem Description
There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !
Input
The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.
Output
For each test case,print the sum of A and B in hexadecimal in one line.
Sample Input
+A -A
+1A 12
1A -9
-1A -12
1A -AA
Sample Output
0
2C
11
-2C
-90
其实就是十六进制的加减。不过以前没遇到过这么大的
#include<iostream>
#include<sstream>
#include<cstring>
#include<algorithm>
#include<set>
#include<cstdio>
using namespace std;
int main(){__int64 a,b;while(scanf("%I64X %I64X",&a,&b)!=EOF){if(a+b>=0){printf("%I64X\n",a+b);}else{ //第一次用到这么大的数据类型，很奇怪，为负数时非要这么写 路过的大佬方便的话解个答 printf("-%I64X\n",-a-b);//这里的x要大写，这样结果输出的格式才会大写 }} return 0;
}