202009-2 风险人群筛查

本题链接：202009-2 风险人群筛查

本博客给出本题截图：

C++

#include <iostream>
#include <cstring>
#include <algorithm>using namespace std;int n, k, t, x1, y1, x2, y2;int main()
{
    cin >> n >> k >> t >> x1 >> y1 >> x2 >> y2;int res1 = 0, res2 = 0;while (n -- ){
    bool r1 = false, r2 = false;int s = 0;for (int i = 0; i < t; i ++ ){
    int x, y;cin >> x >> y;if (x >= x1 && x <= x2 && y >= y1 && y <= y2){
    s ++ ;r1 = true;if (s >= k) r2 = true;}else s = 0;}if (r1) res1 ++ ;if (r2) res2 ++ ;}cout << res1 << endl << res2 << endl;return 0;
}

总结

水题，不解释