新手求教oracle行转列有关问题_Oracle技术

新手求教oracle行转列问题
原表数据：
ID_NO_SZ NAME_SZ BAN DIR DAYS
2000139 孔令波 D01+E01 間接 1
2000139 孔令波 D02+E02 間接 26
2000225 楊長永 D02+E02 間接 24
2000245 潘亞平 D01+E01 直接 24
想转换成如下形式的求高手指点：
ID_NO_SZ NAME_SZ D01+E01 D02+E02 DIR
2000139 孔令波 1 26 間接
2000225 楊長永 0 24 間接
2000245 潘亞平 24 0 直接
（D01+E01 D02+E02 下面的数字为原表的days数值）

------解决方案--------------------
--这两个都行.

SQL code

select ID_NO_SZ ,NAME_SZ,  max(case BAN when 'D01+E01' then DAYS else 0 end) "D01+E01",  max(case BAN when 'D02+E02' then DAYS else 0 end) "D02+E02",  max(DIR) DIRfrom tbgroup by ID_NO_SZ ,NAME_SZselect ID_NO_SZ ,NAME_SZ,  max(decode (BAN ,'D01+E01' , DAYS , 0 )) "D01+E01",  max(decode (BAN ,'D02+E02' , DAYS , 0 )) "D02+E02",  max(DIR) DIRfrom tbgroup by ID_NO_SZ ,NAME_SZ
------解决方案--------------------
SQL codeselect ID_NO_SZ ,NAME_SZ,  max(case BAN when 'D01+E01' then DAYS else 0 end) "D01+E01",  max(case BAN when 'D02+E02' then DAYS else 0 end) "D02+E02",  max(DIR) DIRfrom tbgroup by ID_NO_SZ ,NAME_SZ
------解决方案--------------------
SQL codeselect ID_NO_SZ ,NAME_SZ,  max(decode (BAN ,'D01+E01' , DAYS , 0 )) "TA夜班出勤天数1",  max(decode (BAN ,'D02+E02' , DAYS , 0 )) "TA夜班出勤天数2",  max(DIR) DIRfrom tbgroup by ID_NO_SZ ,NAME_SZ