我现在有这样的数据
怎么用语句实现？？
BH MC SL DCRQ
141 宝钢水库 黑颈鸊鷉 10 2007-2-1
142 宝钢水库 小鸊鷉 44 2007-2-1
143 宝钢水库 织女银鸥 2 2007-2-1
144 宝钢水库 环颈鸻 30 2007-2-1
145 宝钢水库 白腰草鹬 3 2007-2-1
146 宝钢水库 黑颈鸊鷉 6 2007-2-1
在上面的数据中 141 和 146
实现结果想把 141 146合并
并且数量还要想加 保留 相加的结果
删除另外一条
------解决方案--------------------
- SQL code
SQL> create table tbl(bh int,MC nvarchar2(30),sl int,dcrq nvarchar2(10));Table createdSQL> SQL> insert into tbl select 141,N'AA',10,'2007-2-1' from dual;1 row insertedSQL> insert into tbl select 142,N'BB',44,'2007-2-1' from dual;1 row insertedSQL> insert into tbl select 143,N'CC',2,'2007-2-1' from dual;1 row insertedSQL> insert into tbl select 144,N'DD',30,'2007-2-1' from dual;1 row insertedSQL> insert into tbl select 145,N'EE',3,'2007-2-1' from dual;1 row insertedSQL> insert into tbl select 146,N'AA',6,'2007-2-1' from dual;1 row insertedSQL> SQL> select bh,mc,slnew,dcrq from ( 2 select bh,mc,slnew,dcrq,row_number()over(partition by mc,dcrq order by slnew desc) rw from ( 3 select bh,mc,sl,dcrq,sum(sl)over(partition by mc,dcrq order by bh) SLnew from tbl 4 ) 5 ) where rw=1; BH MC SLNEW DCRQ--------------------------------------- ------------------------ ---------- -------------------- 146 AA 16 2007-2-1 142 BB 44 2007-2-1 143 CC 2 2007-2-1 144 DD 30 2007-2-1 145 EE 3 2007-2-1SQL>