存储过程
CREATE OR REPLACE PROCEDURE UpdatePiecesChn(pieceidStr in varchar2,
updateChnid in NUMBER,
fromChnid in number) is
begin
delete from sc_st_chn_ps
where pieceid in (select pieceid
from sc_st_chn_ps
where chnid = updateChnid
and pieceid in (pieceidStr))
and chnid = fromChnid;
update sc_st_chn_ps
set chnid = updateChnid
where pieceid in (pieceidStr)
and chnid = fromChnid;
commit;
end UpdatePiecesChn;
然后调用
exec UpdatePiecesChn('1555,1557,1560,1576,1577,1578,1547,1561,1573,1574,1586,1588,1590,1592,1593,1663,1664,2675,2676,2679,2681,2682,2683,2705,2708,2709,3722,3682,3723,5330,5331,5332,5563',504,198);
会报错误,错误提示信息:ORA-01722: 无效数字
我大概也知道原因是 in后面pieceidStr对应的值不合法
正确的应该是
delete from sc_st_chn_ps
where pieceid in (select pieceid
from sc_st_chn_ps
where chnid = updateChnid
and pieceid in (1555,1557,1560,1576,1577,1578,1547,1561,1573,1574,1586,1588,1590,1592,1593,1663,1664,2675,2676,2679,2681,2682,2683,2705,2708,2709,3722,3682,3723,5330,5331,5332,5563))
而我这边变为了
delete from sc_st_chn_ps
where pieceid in (select pieceid
from sc_st_chn_ps
where chnid = updateChnid
and pieceid in (‘1555,1557,1560,1576,1577,1578,1547,1561,1573,1574,1586,1588,1590,1592,1593,1663,1664,2675,2676,2679,2681,2682,2683,2705,2708,2709,3722,3682,3723,5330,5331,5332,5563’))
请问这个该怎么改? 这一串字符是前台传过来的,谢谢
------解决思路----------------------
这种的用动态拼装sql
CREATE OR REPLACE PROCEDURE UpdatePiecesChn(pieceidStr in varchar2,
updateChnid in NUMBER,
fromChnid in number) is
v_del_sql varchar2(100);
v_upd_sql varchar2(100);
begin
v_del_sql:='delete from sc_st_chn_ps where pieceid in (select pieceid from sc_st_chn_ps where chnid = updateChnid and pieceid in ('
------解决思路----------------------
pieceidStr
------解决思路----------------------
')) and chnid = fromChnid';
v_upd_sql:='update sc_st_chn_ps set chnid = updateChnid where pieceid in ('
------解决思路----------------------
pieceidStr
------解决思路----------------------
') and chnid = fromChnid';
execute immediate v_del_sql;
execute immediate v_upd_sql;
commit;
end UpdatePiecesChn;
------解决思路----------------------
-- 这个出错了,系统 会把 pieceidStr 当做一个数值来看,是一个数值,而不是多个。
???where?pieceid?in?(pieceidStr)
-- 采用楼上的动态语句是一个方法,也可以使用 instr 函数,但是存在一个隐式转化
where instr( ','
------解决思路----------------------
pieceidStr
------解决思路----------------------
',' , ','
------解决思路----------------------
piecdeid
------解决思路----------------------
',') > 0
------解决思路----------------------
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