function sub(arg1, arg2) { var r1, r2, m, n; try { r1 = arg1.toString().split('.')[1].length } catch (e) { r1 = 0 } try { r2 = arg2.toString().split('.')[1].length } catch (e) { r2 = 0 } m = Math.pow(10, Math.max(r1, r2)); //动态控制精度长度 n = (r1 >= r2) ? r1 : r2; return parseFloat(((arg1 * m - arg2 * m) / m).toFixed(n)); } //加法 function add(arg1, arg2) { var r1, r2, m; try { r1 = arg1.toString().split('.')[1].length } catch (e) { r1 = 0 } try { r2 = arg2.toString().split('.')[1].length } catch (e) { r2 = 0 } m = Math.pow(10, Math.max(r1, r2)) return (arg1 * m + arg2 * m) / m } //乘法 function mul(arg1, arg2) { var m = 0, s1 = arg1.toString(), s2 = arg2.toString(); try { m += s1.split('.')[1].length } catch (e) { } try { m += s2.split('.')[1].length } catch (e) { } return Number(s1.replace('.', '')) * Number(s2.replace('.', '')) / Math.pow(10, m) } //除法 function div(arg1, arg2) { var t1 = 0, t2 = 0, r1, r2; try { t1 = arg1.toString().split('.')[1].length } catch (e) { } try { t2 = arg2.toString().split('.')[1].length } catch (e) { } with (Math) { r1 = Number(arg1.toString().replace('.', '')) r2 = Number(arg2.toString().replace('.', '')) return (r1 / r2) * pow(10, t2 - t1); } }?
详细解决方案
JS处置加减乘除误差较大
热度:412 发布时间:2012-11-04 10:42:42.0