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zz怎么在js中获得div的位置(一段封装好的代码)

热度:162   发布时间:2012-11-25 11:44:31.0
zz如何在js中获得div的位置(一段封装好的代码)
function getElementPos(elementId){
    var ua = navigator.userAgent.toLowerCase();
    var isOpera = (ua.indexOf('opera') != -1);
    var isIE = (ua.indexOf('msie') != -1 && !isOpera); // not opera spoof
    var el = document.getElementById(elementId);
    if (el.parentNode === null || el.style.display == 'none') {
        return false;
    }
    var parent = null;
    var pos = [];
    var box;
    if (el.getBoundingClientRect) //IE
    {
        box = el.getBoundingClientRect();
        var scrollTop = Math.max(document.documentElement.scrollTop, document.body.scrollTop);
        var scrollLeft = Math.max(document.documentElement.scrollLeft, document.body.scrollLeft);
        return {
            x: box.left + scrollLeft,
            y: box.top + scrollTop
        };
    }
    else 
        if (document.getBoxObjectFor) // gecko    
        {
            box = document.getBoxObjectFor(el);
            var borderLeft = (el.style.borderLeftWidth) ? parseInt(el.style.borderLeftWidth) : 0;
            var borderTop = (el.style.borderTopWidth) ? parseInt(el.style.borderTopWidth) : 0;
            pos = [box.x - borderLeft, box.y - borderTop];
        }
        else // safari & opera    
        {
            pos = [el.offsetLeft, el.offsetTop];
            parent = el.offsetParent;
            if (parent != el) {
                while (parent) {
                    pos[0] += parent.offsetLeft;
                    pos[1] += parent.offsetTop;
                    parent = parent.offsetParent;
                }
            }
            if (ua.indexOf('opera') != -1 || (ua.indexOf('safari') != -1 && el.style.position == 'absolute')) {
                pos[0] -= document.body.offsetLeft;
                pos[1] -= document.body.offsetTop;
            }
        }
    if (el.parentNode) {
        parent = el.parentNode;
    }
    else {
        parent = null;
    }
    while (parent && parent.tagName != 'BODY' && parent.tagName != 'HTML') { // account for any scrolled ancestors
        pos[0] -= parent.scrollLeft;
        pos[1] -= parent.scrollTop;
        if (parent.parentNode) {
            parent = parent.parentNode;
        }
        else {
            parent = null;
        }
    }
    return {
        x: pos[0],
        y: pos[1]
    };
}

?看的别人博客上的,帮了我大忙啊~传上来,好代码一起分享。

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