问题描述
我正在制作一个 Spleef 插件。 我需要数一数大厅里的人数。
我以为我可以数出大厅中心一定距离内有多少人。 我认为当有人输入命令时,这可能比录音更好。
主.java:
package me.olsyboy.spleef;
import org.bukkit.Bukkit;
import org.bukkit.ChatColor;
import org.bukkit.Location;
import org.bukkit.World;
import org.bukkit.command.Command;
import org.bukkit.command.CommandSender;
import org.bukkit.entity.Player;
import org.bukkit.plugin.java.JavaPlugin;
import org.bukkit.configuration.file.YamlConfiguration;
import java.util.Arrays;
import java.util.List;
public class Main extends JavaPlugin {
public void onEnable(int amountOfPlayers) {
amountOfPlayers = 0;
loadConfiguration();
reloadConfig();
}
public void onDisable() {
saveDefaultConfig();
}
public void loadConfiguration() {
//See "Creating you're defaults"
getConfig().options().copyDefaults(true); // NOTE: You do not have to use "plugin." if the class extends the java plugin
//Save the config whenever you manipulate it
saveDefaultConfig();
}
@Override
public boolean onCommand(CommandSender sender, Command cmd, String label, String[] args) {
Player player = (Player) sender;
if (cmd.getName().equalsIgnoreCase("spleef")) {
if (args[0].equalsIgnoreCase("setgame")) {
if (args.length == 2) {
String gameName = args[1]; //initialize the gameName variable here
getConfig().set("Game Locations." + gameName + ".Location", Arrays.asList(player.getLocation().getX(), player.getLocation().getY(), player.getLocation().getZ(), player.getLocation().getPitch(), player.getLocation().getYaw(), player.getLocation().getWorld().getName()));
getConfig().options().copyDefaults(true);
saveConfig();
player.sendMessage(ChatColor.AQUA + "[Spleef] " + ChatColor.YELLOW + "Spleef Game Location Set");
}
}
if (args[0].equalsIgnoreCase("join")) {
String gameName = args[1]; //initialize the gameName variable here
List<String> joinGameLocation = this.getConfig().getStringList("Game Locations." + gameName + ".Location");
String xPos = joinGameLocation.get(0);
double xPos2 = Double.parseDouble(xPos);
String yPos = joinGameLocation.get(1);
double yPos2 = Double.parseDouble(yPos);
String zPos = joinGameLocation.get(2);
double zPos2 = Double.parseDouble(zPos);
String pitch = joinGameLocation.get(3);
float pitch2 = Float.parseFloat(pitch);
String Yaw = joinGameLocation.get(4);
float Yaw2 = Float.parseFloat(Yaw);
World actualWorld = Bukkit.getWorld(joinGameLocation.get(5));
Location spleefGameLocation = new Location(actualWorld, xPos2, yPos2, zPos2);
spleefGameLocation.setPitch(pitch2);
spleefGameLocation.setYaw(Yaw2);
player.teleport(spleefGameLocation);
}
else if (!(args[0].equalsIgnoreCase("setgame"))) {
if (!args[0].equalsIgnoreCase("join")) {
player.sendMessage("/spleef join {GameName}");
}
}
}
return true;
}
}
playerJoinedGame.java:
package me.olsyboy.spleef;
public class playerJoinedGame extends Main {
public void onPlayerJoin(int amountOfPlayers)
{
amountOfPlayers = amountOfPlayers + 1;
}
}
我还没有从主类调用onPlayerJoin
方法。
我对任何有更好方法来计算大厅人数的人持开放态度。
1楼
确保您有一个Location
对象,其中心是您想要获取附近玩家的中心。
Location center = new Location(world, x, y, z);
然后,具有所需距离的double
值。
double distance = 10D;
首先,您应该对服务器上的所有玩家进行循环:
for (Player player : Bukkit.getOnlinePlayers()) {
}
然后,获取player
的位置:
for (Player player : Bukkit.getOnlinePlayers()) {
Location location = player.getLocation();
}
现在我们可以检查两个位置( center
和location
)之间的距离:
for (Player player : Bukkit.getOnlinePlayers()) {
Location location = player.getLocation();
if (location.distanceSquared(center) <= distance * distance) {
// Do something
}
}
注意:您应该使用distanceSquared(Location)
这相当于结果平方distance(Location)
,因为distance(Location)
使用Java的平方根法,这是非常耗费大量资源。
最后结果:
double distance = 10D;
Location center = new Location(Bukkit.getWorld("world"), x, y, z);
for (Player player : Bukkit.getOnlinePlayers()) {
Location location = player.getLocation();
if (location.distanceSquared(center) <= distance * distance) {
// Do something
}
}
2楼
loc.getWorld().getNearbyEntities(loc, distance, distance, distance).stream()
.filter(e -> e instanceof Player)
.findFirst()
.orElse(null);
就这样做