spring+cxf+jdbc,该如何处理

        @Test    public void testSaveOrUpdate(){        String url = "http://localhost:8081/services/userservices/adduser";        HttpClient httpClient = new HttpClient();        PostMethod postMethod = new PostMethod(url);        postMethod.setRequestHeader("Content-type","application/xml");        postMethod.setRequestHeader("user", "vis");        postMethod.setRequestHeader("pass", "vis@amoy");        postMethod.setRequestEntity(new InputStreamRequestEntity(this.getClass().getResourceAsStream("testAddUsers.xml")));        try{            int status = httpClient.executeMethod(postMethod);            if(status == HttpStatus.SC_OK){                System.out.println(new String(postMethod.getResponseBody(), "utf-8"));            }        }catch (HttpException e) {            throw new RuntimeException("",e);        } catch (IOException e) {            throw new RuntimeException("",e);        }finally{            postMethod.releaseConnection();        }    }

@Path("/userservices/")@Produces("application/xml")public class UserService {    @Context    private org.apache.cxf.jaxrs.ext.MessageContext messageContext;        @POST    @Path("/adduser")    @Consumes("application/xml")    public Response saveOrUpdate(VisUsers users) {        if(Authentication.validate(messageContext)){        int result=userDao.saveOrUpdate(users);        if(result>0){            return Response.status(200).entity("Save OK!").build();        }else{            return Response.status(401).entity("insert user error!").build();        }        }else{            return Response.status(401).build();        }    }

<bean id="userservices" class="com.sns.bestv.service.impl.UserService">        <property name="userDao" ref="userDao"></property>    </bean>        <jaxrs:server id="mmberService_wa" address="/">        <jaxrs:serviceBeans>            <ref bean="mmberService" />            <ref bean="userservices" />        </jaxrs:serviceBeans>    </jaxrs:server>