给出一个乱序的list<Seat>,Seat里面有int类型的rowNum（排号）和line座位号，怎么得到先排好序的（先比较rowNum，相同则比较 line 从小到大）的list？
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- Java code
import java.util.ArrayList;import java.util.Collections;import java.util.Comparator;import java.util.List;class Seat { private int rowNumber; private int line; public Seat(int rowNumber, int line) { this.rowNumber = rowNumber; this.line = line; } public int getRowNumber() { return rowNumber; } public void setRowNumber(int rowNumber) { this.rowNumber = rowNumber; } public int getLine() { return line; } public void setLine(int line) { this.line = line; } @Override public String toString() { return rowNumber + " " + line; }}//比较规则class SeatComparator implements Comparator<Seat> { public int compare(Seat o1, Seat o2) { return (o1.getRowNumber() < o2.getRowNumber() ? -1 : (o1.getRowNumber()> o2.getRowNumber() ? 1: ( o1.getLine() < o2.getLine() ? -1 : (o1.getLine()> o2.getLine() ? 1 :0 )))); }}public class TestSeat { public static void main(String[] args) { Seat s1 = new Seat(1, 1); Seat s2 = new Seat(3, 1); Seat s3 = new Seat(2, 4); Seat s4 = new Seat(3, 2); List<Seat> seats = new ArrayList<Seat>(); seats.add(s1); seats.add(s2); seats.add(s3); seats.add(s4); System.out.println("原始数据:"); for (Seat seat : seats) { System.out.println(seat); } System.out.println("进行排序......"); SeatComparator seatComparator = new SeatComparator(); Collections.sort(seats, seatComparator); for (Seat seat : seats) { System.out.println(seat); } }}/*原始数据:1 13 12 43 2进行排序......1 12 43 13 2*/