11． programmers.json文件中包含如下内容：
{ "programmers": [ { "firstName": "Brett", "lastName":"McLaughlin", "email": "brett@newInstance.com" }, { "firstName": "Jason", "lastName":"Hunter", "email": "jason@servlets.com" }, { "firstName": "Elliotte", "lastName":"Harold", "email": "elharo@macfaq.com" } ],"authors": [ { "firstName": "Isaac", "lastName": "Asimov", "genre": "science fiction" }, { "firstName": "Tad", "lastName": "Williams", "genre": "fantasy" }, { "firstName": "Frank", "lastName": "Peretti", "genre": "christian fiction" } ],"musicians": [ { "firstName": "Eric", "lastName": "Clapton", "instrument": "guitar" }, { "firstName": "Sergei", "lastName": "Rachmaninoff", "instrument": "piano" } ]}
从文件获取programmers、authors 和 musicians的信息，做以下处理：
1. 在控制台输出Jason,Isaac,Sergei的相关信息（firstName,lastName等）
2. 将分析得到的programmers、authors 和 musicians的信息，以json格式输出到people.json文件中
3. 将programmers.json的内容转换为XML格式,根元素为data.
求该题的完整代码！新手刚入门，还请各位高手多多指教，不胜感激！
------解决方案--------------------------------------------------------
就是用file读取文件内容（应该是按行读取）
再用JSONObject解析就行了。
------解决方案--------------------------------------------------------
- Java code
private ObjectMapper mapper; private List<AppConfig> appConfig; public AppConfigController() { String propsFile = AppConfigController.class.getResource("/").toString().replace("file:", "") + "appConfig.cfg"; this.mapper = new ObjectMapper(); this.mapper.setAnnotationIntrospector(new NopAnnotationIntrospector()); try { propsFile = java.net.URLDecoder.decode(propsFile,"utf-8"); logger.info("获取到配置文件路径{}", new File(propsFile).getAbsolutePath()); this.appConfig = mapper.readValue(new File(propsFile), new TypeReference<List<AppConfig>>() { }); } catch (Exception e) { e.printStackTrace(); logger.warn(e.getMessage() + "配置文件路径：{}", propsFile); } }
------解决方案--------------------------------------------------------
解决了？那就结贴吧