java多线程找零问题，我想知道我的程序运行后为什么得不到正确的结果？
在线求高手解决：package Exercise2;
import java.awt.*;
import javax.swing.*;
public class ThreadTest_02 {
static SalesLady saleslady = new SalesLady(14, 0, 0, 0);
public static void main(String[] args) {
new ThreadTest_02().start();
}
public void start() {
int moneies[] = { 10, 20, 5, 10, 5, 10, 5, 50, 100, 10, 5, 10, 20, 5,
10, 5 };
Thread[] aThreadArray = new Thread[moneies.length];
System.out.println("现在开始售票：");
for (int i = 0; i < moneies.length; i++) {
aThreadArray[i] = new Thread(new CustomerClass(i + 1, moneies[i]));
aThreadArray[i].start();
}
for (int i = 0; i < moneies.length; i++) {
try {
aThreadArray[i].join();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println("票已售完");
}
}
// 顾客 销售人员
class SalesLady {
int memontoes, five, ten, twenty, fifty, hundred;
String s = null;
SalesLady(int m, int f, int t, int ty) {
memontoes = m;
five = f;
ten = t;
twenty = ty;
}
public synchronized String ruleForSale(int num, int money) {
if (memontoes <= 0)
return s = "对不起，已经售完";
if (money == 5) {
memontoes--;
five++;
s = "给你票，你的钱正好。";
notify();
} else if (money == 10) {
if (five >= 1) {
memontoes--;
five -= 1;
ten++;
s = "给你票，找你5元。";
} else {
s = num + "号顾客用10元购票，请等待";
// notify();
try {
wait();
} catch (InterruptedException e) {
}
}
notify();
} else
if (money == 20) {
twentyGive();
notify();
} else if (money == 50) {
// notify();
fiftyGive();
// notify();
} else if(money == 100) {
hundredGive();
notify();
}
notifyAll();
return s;
}
public void twentyGive() {
if (ten >= 1 && five >= 1) {
s = "找您1个10元1个5元！";
ten--;
five--;
twenty++;
memontoes--;
} else if (ten < 1 && five >= 3) {
s = "给您球票，找您3个5元，请在球赛开始前进影院观看精彩比赛！";
five -= 3;
memontoes--;
twenty++;
} else {
s = ": 不好意思，暂时没有零钱找，请稍等，！";
try {
wait();
} catch (InterruptedException e) {
s = " 不好意思，暂时没有零钱找，请稍等，！";
}
}
// return ;
}
public void fiftyGive() {
if (twenty >= 2 && five >= 1) {
s = ": 给您球票，找您2个20元和1个5元，请在球赛开始前进影院观看精彩比赛！\n";
five--;
twenty -= 2;
fifty++;
memontoes--;
} else if (twenty >= 1 && ten >= 2 && five >= 1) {
s = ": 给您球票，找您1个20元2个10元和1个5元，请在球赛开始前进影院观看精彩比赛！\n";
five--;
twenty--;
ten -= 2;
fifty++;
memontoes--;
} else if (twenty < 1 && ten >= 4 && five >= 1) {
s = ": 给您球票，找您45元钱，请在球赛开始前进影院观看精彩比赛！\n";
five--;
ten -= 4;
fifty++;
memontoes--;
} else if (twenty < 1 && ten >= 3 && five >= 3) {
s = ": 给您球票，找您45元钱，请在球赛开始前进影院观看精彩比赛！\n";
five -= 3;
ten -= 3;
fifty++;
memontoes--;
} else if (twenty < 1 && ten >= 2 && five >= 5) {
s = ": 给您球票，找您45元钱，请在球赛开始前进影院观看精彩比赛！\n";
five -= 5;
ten -= 2;
fifty++;
memontoes--;
} else if (twenty < 1 && ten >= 1 && five >= 7) {
s = ": 给您球票，找您45元钱，请在球赛开始前进影院观看精彩比赛！\n";
five -= 7;
ten--;
fifty++;
memontoes--;
} else if (twenty < 1 && ten < 1 && five >= 9) {
s = ": 给您球票，找您45元钱，请在球赛开始前进影院观看精彩比赛！\n";
five -= 9;
fifty++;
memontoes--;
} else {
s = ": 不好意思，暂时没有零钱找，请稍等，！";
try {
wait();
} catch (InterruptedException e) {
System.out.println("等待状态！");
}
}
notify();
}
/*
* 100元找钱方法，使用最有方法找零钱
*/
public void hundredGive() {
if (fifty >= 1 && twenty >= 2 && five >= 1) {
fifty--;
twenty -= 2;
five--;
hundred++;
memontoes--;
s = ": 给您球票，找您95元钱，请在球赛开始前进影院观看精彩比赛！\n";
} else if (fifty < 1 && twenty >= 4 && five >= 1) {
five--;
twenty -= 4;
ten -= 4;
hundred++;
memontoes--;
s = ": 给您球票，找您95元钱，请在球赛开始前进影院观看精彩比赛！\n";
} else if (fifty < 1 && twenty >= 3 && ten >= 3 && five >= 1) {
five--;
ten -= 3;
twenty -= 3;
hundred++;
memontoes--;
s = ": 给您球票，找您95元钱，请在球赛开始前进影院观看精彩比赛！\n";
} else if (fifty < 1 && twenty >= 2 && ten >= 5 && five >= 1) {
five -= 1;
ten -= 5;
fifty++;
memontoes--;
s = ": 给您球票，找您95元钱，请在球赛开始前进影院观看精彩比赛！\n";
} else if (fifty < 1 && twenty >= 1 && ten >= 7 && five >= 5) {
five -= 5;
ten -= 7;
fifty++;
memontoes--;
s = ": 给您球票，找您95元钱，请在球赛开始前进影院观看精彩比赛！\n";
} else {
s = ": 不好意思，暂时没有零钱找，请稍等，！\n";
try {
wait();
} catch (InterruptedException e) {
System.out.println("等待状态！");
}
}
notify();
}
}
// 顾客
class CustomerClass implements Runnable {
int num, money;
public void run() {
System.out.println("我是" + num + "号顾客，用" + money + "元购票\n售票员说："
+ ThreadTest_02.saleslady.ruleForSale(num, money));
}
/*
* 顾客编号及给的钱的数量
*/
CustomerClass(int n, int m) {
num = n;
money = m;
}
}
----------------解决方案--------------------------------------------------------
建议不要用线程组了，是不是看的教材太老了。
----------------解决方案--------------------------------------------------------
请楼上的高手给出解决办法，感激不尽…………
----------------解决方案--------------------------------------------------------
程序很乱，看不明白，先提出你的程序功能需求，
----------------解决方案--------------------------------------------------------
使用图形化界面模拟多人排队买车票，假设车票5元一张，购票者有持5元、10元、20元、50元、100元的。已知排队者持钱情况序列，使用多线程模拟购票。
----------------解决方案--------------------------------------------------------
一楼真实高手，一眼就能看出楼主的教材过老，佩服佩服
----------------解决方案--------------------------------------------------------