要求用一个类确定二位数列中最大值和最大值的位置。这个类包含public data field row,column,and maxValue去储存最大值和它的index，这个数列的row和column是整数类型，maxValue是double类型。使用public static Location locationLargest(double [][] a)作为类函数获得二维函数中最大值的位置。获得的值是一个instance of location. 用一个test 程序让用户输入一个二位数列，别且显示数列中最大值的位置。
以下是sample：
Enter the number of rows and columns of the array: 3 4
enter the array
35 2 10 4.3
23.5 4.5 3 45
33 44 5.5 9.6
The location of the largest element is 45 at (2,4)
哪位大神能帮忙做一下么，谢谢了。
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- Java code
import java.util.Scanner;public class Test { static class Location{ int row,col; double max; public Location(int row,int col,double max){ this.row = row; this.col = col; this.max = max; } public int getRow() { return row; } public int getCol() { return col; } public double getMax() { return max; } } public static void main(String[] args) { Scanner scanner = new Scanner(System.in); double[][] arr = null; try { System.out.println("Enter the number of rows and columns of the array:"); String input = scanner.next(); int row = Integer.valueOf(input); input = scanner.next(); int col = Integer.valueOf(input); arr = new double[row][col]; System.out.println("enter the array"); for(int i = 0;i < row;i++){ for(int j = 0;j < col;j++){ input = scanner.next(); arr[i][j] = Double.valueOf(input); } } } catch (Exception e) { System.out.println("input error"); } Location location = locationLargest(arr); System.out.println("The location of the largest element is " + location.getMax() + " at (" + (location.getRow() + 1) + "," + (location.getCol() + 1) + ")"); } static Location locationLargest(double[][] a){ Location location = new Location(0,0,a[0][0]); for(int i = 0;i < a.length;i++){ for(int j = 0;j < a[0].length;j++){ if(a[i][j] > location.getMax()){ location = new Location(i,j,a[i][j]); } } } return location; }}
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- Java code
import java.util.Scanner;public class TestSync { public static void main(String args[]) { Scanner s = new Scanner(System.in); int countX = 0, countY = 0; double[][] data = null; for (;;) { System.out .print("Enter the number of rows and columns of the array:"); String str = s.nextLine(); try { String[] temp = str.split("\\s+"); data = new double[Integer.valueOf(temp[0])][Integer .valueOf(temp[1])]; } catch (Exception e) { continue; } break; } countX = data.length; countY = data[0].length; double max = Double.MIN_NORMAL; int maxIndexX = -1; int maxIndexY = -1; boolean exitFlag = false; while (!exitFlag) { System.out.println("Enter the array:"); exitFlag = true; for (int index = 0; index < countX * countY; index++) { try { data[index / countY][index % countY] = s.nextDouble(); if (max < data[index / countY][index % countY]) { maxIndexX = index / countY; maxIndexY = index % countY; max = data[index / countY][index % countY]; } } catch (Exception e) { exitFlag = false; break; } } } System.out.println("The location of the largest element is " + max + " at ( " + maxIndexX + "," + maxIndexY + ")"); }}