再帮我解决一下!!谢谢!
用什么函数连续接收用户输入的5个数字,并能操纵这5个数字??是readin()么?
eg： 请用户输入5~15之间的5个数字,并用横状图表示.
5 2 7 10 3
*****
**
*******
**********
***
[此贴子已经被作者于2005-9-11 21:18:51编辑过]
----------------解决方案--------------------------------------------------------
// 程序运行时，数字是一个一个输入的
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
class Keyboard
{
private static String getEingabe()
{
String eingabe;
BufferedReader reader;
reader = new BufferedReader( new InputStreamReader( System.in ) );
try
{
eingabe = reader.readLine();
return eingabe;
}
catch ( IOException e )
{
e.printStackTrace();
}
return null;
}
public static int getInteger()
{
String eingabe;
do
{
eingabe = getEingabe();
}while(checkIntegerInput(eingabe) == false);
int zahl = Integer.parseInt( eingabe );
return zahl;
}
public static double getDouble()
{
String eingabe = getEingabe();
double zahl = Double.parseDouble( eingabe );
return zahl;
}
public static String getString()
{
String eingabe = getEingabe();
return eingabe;
}
public static boolean checkIntegerInput(String s)
{
char [] c = s.toCharArray();
for(int i = 0; i<c.length; i++)
{
int d = (int)c[i];
if(d<48 || d>57)
{
MyException e = newMyException("Invalid input, you should input all integer number");
return false;
}
}
return true;
}
}
class MyException
{
MyException(String s)
{
System.err.println(s);
System.out.println("Please try enter a new number between 5 and 15,inclusive 5 and 15.");
}
public int tryAgain()
{
return Keyboard.getInteger();
}
}
public class PrintAsterisk
{
public PrintAsterisk()
{
int [] nums = new int[5];
for(int i = 0; i<nums.length; i++)
{
System.out.println("Please input an integer number between 5 and 15, inclusive");
nums[i] = Keyboard.getInteger();
while(nums[i] > 15 || nums[i] < 5)
{
MyException e = new MyException("invalid input");
nums[i] = e.tryAgain();
}
}
for(int i = 0; i<nums.length; i++)
{
for(int j = 0; j<nums[i]; j++)
{
System.out.print("*");
}
System.out.println();
}
}
public static void main(String [] args)
{
PrintAsterisk pa = new PrintAsterisk();
}
}
----------------解决方案--------------------------------------------------------
import java.io.*;
class xiti3
{
public static void main (String[] arg)
{
int a[]=0;
DataInputStream in = new DataInputStream(System.in);
try
{
for(int i=0;i<5;i++)
{
System.out.print("请输入1~15之间的一个数字：");
a[i]=Integer.parseInt(in.readLine());
}
while (int i>0)
{
int i=5;
System.out.print("您输入了以下5个数字：");
System.out.print(a[i]);
i--;
}
for(int j=0;j<5;j++)
{
for(int k=1;k<=a[j];k++)
System.out.print("*");}
System.out.println("");
}catch(Exception e){
}
}
}
这是我写的一个,不知道哪里错了,希望大家帮我看看!!
[此贴子已经被作者于2005-9-11 21:21:09编辑过]
----------------解决方案--------------------------------------------------------
// 如果不做严格要求的话，那么勉强可以通过
import java.io.*;
class xiti3
{
public static void main (String[] arg)
{
int a[]=new int[5]; // here pay attention
DataInputStream in = new DataInputStream(System.in);
try
{
for(int i=0;i<5;i++)
{
System.out.print("请输入1~15之间的一个数字：");
a[i]=Integer.parseInt(in.readLine());
}
System.out.print("您输入了以下5个数字：");
int i =5; // and here this while loop pay attention
while (i>0)
{
System.out.print(a[5-i] + " ");
i--;
}
System.out.println();
for(int j=0;j<5;j++)
{
for(int k=0;k<a[j];k++)
{
System.out.print("*");
}
System.out.println();
}
}
catch(Exception e)
{
System.err.println(e.toString());
}
}
}
----------------解决方案--------------------------------------------------------
HI! 帅哥一族 你的答案
import java.io.*;
class xiti3
{
public static void main (String[] arg)
{
int a[]=new int[5];
int b=5;
DataInputStream in = new DataInputStream(System.in);
try
{
for(int i=0;i<5;i++)
{
System.out.print("请输入1~15之间的一个数字：");
a[i]=Integer.parseInt(in.readLine());
}
System.out.println("您输入了以下5个数字：");
for (int i = 0; i<5; i++)
{
System.out.println (a[i]);
}
for(int j=0;j<5;j++)
{
for(int k=1;k<=a[j];k++)
{
System.out.print("*");
}
System.out.println("");
}
}
catch(Exception e){ }
}
}
----------------解决方案--------------------------------------------------------
谢谢两位~~~~问题已解决!!!!!!!!!!
----------------解决方案--------------------------------------------------------