import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;
public class MyTestServlet extends HttpServlet{
private static final String CONTENT_TYPE= "text/html;charset=GB2312 ";
public void init(ServletConfig config) throws ServletException{
super.init(config);
}
public void doGet(HttpServletRequest request,HttpServletResponse response)
throws ServletException,IOException{
response.setContentType(CONTENT_TYPE);
PrintWriter out = response.getWriter();
out.print( " <html> ");
out.println( " <head> <title> MyTestServlet 小应用程序 </title> </head> ");
out.print( " <body> ");
out.print( " <p> MyTestServlet 小应用程序 </p> ");
out.print( " </body> </html> ");
}
public void destroy(){
}
}
web.xml
<?xml version= "1.0 " encoding= "ISO-8859-1 "?>
<web-app xmlns= "http://java.sun.com/xml/ns/j2ee "
xmlns:xsi= "http://www.w3.org/2001/XMLSchema-instance "
xsi:schemaLocation= "http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd "
version= "2.4 ">
<display-name> Welcome to Tomcat </display-name>
<description>
Welcome to Tomcat
</description>
<!-- JSPC servlet mappings start -->
<servlet>
<servlet-name> MyTestServlet </servlet-name>
<servlet-class> LianXi.MyTestServlet </servlet-class>
</servlet>
<servlet-mapping>
<servlet-name> MyTestServlet </servlet-name>
<url-pattern> /LianXi/MyTestServlet </url-pattern>
</servlet-mapping>
<!-- JSPC servlet mappings end -->
</web-app>
------解决方案--------------------
LianXi.MyTestServlet 确认包名是否正确？
访问的路径是这个吗 http://localhost/LianXi/MyTestServlet
你给的信息太少了
------解决方案--------------------
错误信息贴出来啊！
------解决方案--------------------
首先，如果你的项目根context是LianXi的话（默认都是web项目的名称），那么你想请求这个servelt应该在输入：http://localhost:8080/LianXi/LianXi/MyTestServlet。
说白了就是上下文路径没有找对。
如果你是在%TOMCAT_HOME%\webapps\LianXi目录下的某个jsp文件中访问这个servlet的话（比如是index.jsp）就应该这样写：
<form action= "servlet/MyTestServlet " method= "get ">
<input type= "submit " value= "submit ">
</form>
而你的web.xml中的servlet映射就应该这样配置:
<servlet-mapping>
<servlet-name> MyTestServlet </servlet-name>